Question

A 1500-kg car drives at 30 m/s around a flat circular track 300 m in diameter. What are the magnitude and direction of the net force on the car?

Answer 1

Answer:

F=9000N

Direction is towards the center

Explanation:

Car is moving in a circular path so the force acting on the car is the centrifugal force which is always towards the center. In order to find that force we will use the following formula:

$F=\frac{mv^{2} }{r}$

Where:

F is the centrifugal force

m is the mass of object

v is the velocity of object

r is the radius of circular path

Since diameter is given then r=diameter/2

r=300/2

r=150m

$F=\frac{1500*30^{2} }{150}$

F=9000N

Direction is towards the center

So the magnitude of the force is 9000N and the direction is towards the center of circular track as car is moving in circular path.