Complete question:
An air-filled parallel-plate capacitor has plates of area 2.90 cm2 separated by 2.50 mm. The capacitor is connected to a(n) 18.0 V battery. Find the value of its capacitance.
Answer:
The value of its capacitance is 1.027 x 10⁻¹² F
Explanation:
Given;
area of the plate, A = 2.9 cm² = 2.9 x 10⁻⁴ m²
separation distance of the plates, d = 2.5 mm = 2.5 x 10⁻³ m
voltage of the battery, V = 18 V
The value of its capacitance is calculated as;

Therefore, the value of its capacitance is 1.027 x 10⁻¹² F
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Answer:
<em>20cm</em>
Explanation:
<em>A coil wire comprises of 5 turns, it has a current of 2mA </em>
<em>A net magnetic field at the center of B is equal to Mu over 40 end fractions times T</em>
<em>The radius of a coil of wire with N turns is r = 0.28 m. A clockwise current of Icoil = 1.0 A flows in the coil,</em>
<em>Therefore 40/2mA = 20</em>
Answer:
Yes. The current is actually flow of charge and in actual situation electrons flow from negative terminal to positive terminal. But in physics the convention of positive charge flow is used i.e. we take the direction of current from positive to negative terminal.
Explanation: