A 1500-kg car drives at 30 m/s around a flat circular track 300 m in diameter. What are the magnitude and direction of the net f
1 answer:
Answer:
F=9000N
Direction is towards the center
Explanation:
Car is moving in a circular path so the force acting on the car is the centrifugal force which is always towards the center. In order to find that force we will use the following formula:
Where:
F is the centrifugal force
m is the mass of object
v is the velocity of object
r is the radius of circular path
Since diameter is given then r=diameter/2
r=300/2
r=150m
F=9000N
Direction is towards the center
So the magnitude of the force is 9000N and the direction is towards the center of circular track as car is moving in circular path.
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, (iii)
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(i) and
represent the points where particle has a velocity of zero and spring reach maximum deformation, Given the absence of non-conservative force and by the Principle of Energy Conservation, the position where particle is at maximum speed is average of both extreme positions:
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.
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Answer:
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133.33 K
Explanation:
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Melting occurs at 133.33 K