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Vedmedyk [2.9K]
3 years ago
6

A 1500-kg car drives at 30 m/s around a flat circular track 300 m in diameter. What are the magnitude and direction of the net f

orce on the car?
Physics
1 answer:
Ahat [919]3 years ago
3 0

Answer:

F=9000N

Direction is towards the center

Explanation:

Car is moving in a circular path so the force acting on the car is the centrifugal force which is always towards the center. In order to find that force we will use the following formula:

F=\frac{mv^{2} }{r}

Where:

F is the centrifugal force

m is the mass of object

v is the velocity of object

r is the radius of circular path

Since diameter is given then r=diameter/2

r=300/2

r=150m

F=\frac{1500*30^{2} }{150}

F=9000N

Direction is towards the center

So the magnitude of the force is 9000N and the direction is towards the center of circular track as car is moving in circular path.

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The answer is A. Cementing...

Explanation:

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During the last shot of the game, the basketball goes from rest to 15 m/s and reaches the backboard in 0.41 s. What was the acce
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Answer: a= 37m

Explanation: V= 15 m/s (Velocity) t= 0.41s (time) formula: a= v/t

15 m/s / 0.41 (15 divided by 0.41) = 36.583m

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How much of the Moon is always illuminated one time? Explain your answer.
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50% of it .

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3 years ago
Suppose that you can throw a projectile at a large enough v0 so that it can hit a target a distance R downrange. Given that you
NikAS [45]

Answer:

Theta1 = 12° and theta2 = 168°

The solution procedure can be found in the attachment below.

Explanation:

The Range is the horizontal distance traveled by a projectile. This diatance is given mathematically by Vo cos(theta) t. Where t is the total time of flight of the projectile in air. It is the time taken for the projectile to go from starting point to finish point. This solution assumes the projectile finishes uts motion on the same horizontal level as the starting point and as a result the vertical displacement is zero (no change in height).

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7 0
3 years ago
A water wheel rotates with a period of 2.26 s. If the water wheel has a radius of l.94 m,
Dafna11 [192]

Answer:

The correct answer is B)

Explanation:

When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel.  So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.

The formula for calculating the velocity of a point on the edge of the wheel is given as

V_{r} = 2π r / T

Where

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T is period of time

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The answer is left in Meters/Seconds so we will work with our information as is given in the question.

Vr = (2 x 3.14159 x 1.94m)/2.26

Vr = 12.1893692/2.26

Vr = 5.39352619469

Which is approximately 5.39

Cheers!

7 0
3 years ago
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