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Vedmedyk [2.9K]
3 years ago
6

A 1500-kg car drives at 30 m/s around a flat circular track 300 m in diameter. What are the magnitude and direction of the net f

orce on the car?
Physics
1 answer:
Ahat [919]3 years ago
3 0

Answer:

F=9000N

Direction is towards the center

Explanation:

Car is moving in a circular path so the force acting on the car is the centrifugal force which is always towards the center. In order to find that force we will use the following formula:

F=\frac{mv^{2} }{r}

Where:

F is the centrifugal force

m is the mass of object

v is the velocity of object

r is the radius of circular path

Since diameter is given then r=diameter/2

r=300/2

r=150m

F=\frac{1500*30^{2} }{150}

F=9000N

Direction is towards the center

So the magnitude of the force is 9000N and the direction is towards the center of circular track as car is moving in circular path.

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Answer:

You drop a rock from rest out of a window on the top floor of a building, 30.0 m above the ground. When the rock has fallen 3.00 m, your friend throws a second rock straight down from the same window. You notice that both rocks reach the ground at the exact same time. What was the initial velocity of the ...... rest out of a window on the top floor of a building, 30.0m above the ground. ... You Notice That Both Rocks Reach The Ground At The Exact Same Time. ... You drop a rock from rest out of a window on the top floor of a building, 30.0m ... When the rock has fallen 3.20 m, your friend throws a second rock straight down from ...

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2 years ago
An Airbus A350 is initially moving down the runway at 6.0 m/s preparing for takeoff. The pilot pulls on the throttle so that the
alexdok [17]

Answer:

t=67.7s

Explanation:

From this question we know that:

Vo = 6m/s

a = 1.8 m/s2

D = 1500m

And we also know that:

X=V_{o}*t + \frac{a*t^{2}}{2}   Replacing the known values:

1500=6t+0.9*t^{2}    Solving for t we get 2 possible answers:

t1 = -44.3s   and t2 = 67.7s    Since negative time represents an instant before the beginning of the movement, t1 is discarded. So, the final answer is:

t = 67.7s

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How do you calculate elastic potential energy
Nimfa-mama [501]
U=1/2kx2

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3 years ago
HELP ME DO THIS QUESTION PLEASE ​
raketka [301]

Answer:

i dont know

Explanation:

but what you can do is ask you mom or dad to get you a tutor to help you

7 0
3 years ago
A water wheel rotates with a period of 2.26 s. If the water wheel has a radius of l.94 m,
Dafna11 [192]

Answer:

The correct answer is B)

Explanation:

When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel.  So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.

The formula for calculating the velocity of a point on the edge of the wheel is given as

V_{r} = 2π r / T

Where

π is Pi which mathematically is approximately 3.14159

T is period of time

Vr is Velocity of the point on the edge of the wheel

The answer is left in Meters/Seconds so we will work with our information as is given in the question.

Vr = (2 x 3.14159 x 1.94m)/2.26

Vr = 12.1893692/2.26

Vr = 5.39352619469

Which is approximately 5.39

Cheers!

7 0
2 years ago
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