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zysi [14]
3 years ago
7

Given f(x)=8x^5, find f^-1(x) Then state whether f^1(x) is a function.

Mathematics
1 answer:
irina1246 [14]3 years ago
6 0

Answer:

f^-1(x) = (x/8)^(1/5) is a function

Step-by-step explanation:

The inverse of a function is the function reflected across the line y=x. This results in the coordinate points (x,y) of the function becoming (y,x) for the inverse function. Algebraically to find the inverse, switch the x and y locations and solve for y.

y = 8x^5

x = 8y^5

x/8 = y^5

(5)√(x/8) = y

This is a fifth root of (x/7) also written in exponents as y = (x/8)^(1/5).

This is a function. While it appears not to be a function because the middle portion over the origin appears vertical, it is a function because the middle portion over the origin is changing and graphing software shows it has no input with more than one output. Without graphing software you would rule it is not a function.

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Two numbers have a sum of 761 and a difference of 335.what are the 2 numbers ​
melisa1 [442]

Answer:

548 and 213

Step-by-step explanation:

Use a linear function:

Let x = 1st number

Let y = 2nd number

x+y=761

x-y=335

2x=1096

x=548

plug x into either equation

548+y=761

y=761-548

y=213

548-y=335

-y=-213

y=213

6 0
3 years ago
ANSWER THIS QUICK QUESTION FOR 30 POINTS!
nika2105 [10]

In triangle A B C

sides A B and B C are formed an angle ABC or angle B

Answer

angle B

4 0
3 years ago
If angles a & b are vertical angles and the measure of angle a is 123 degrees and the measure of angle b is 3x, what is the
dusya [7]

Answer:

x = 41

Step-by-step explanation:

vertical angles are congruent , then

3x = 123 ( divide both sides by 3 )

x = 41

3 0
2 years ago
What is the value of ?<br> 2<br> 3 <br> 4<br> 5
Fed [463]

Answer:

idk what your asking but assuming u mean multiplying the answer is 120

Step-by-step explanation:

8 0
2 years ago
The Oxy coordinate plane for two parallel lines a and a' has the equations 2x - 3y-1 = 0 and 2x - 3y + 5 = 0. respectively. Whic
Andru [333]

Answer:

Remember that a vector translation can be written as:

T(a, b)

And if we apply this to a random point, (x, y), the translation gives:

T(a, b)(x, y) = (x + a, y + b)

now, remember that a general line can be written as:

y = m*x + s

Then a point of that line can be written as: (x, m*x + s)

Then if we apply the translation to a point in the line, we get:

T(a, b)(x, m*x + s) = (x + a, m*x + s + b)

Here we have two lines:

2x - 3y - 1 = 0

2x - 3y + 5 = 0

First, let's rewrite both of these in the slope-intercept form:

y = (2/3)*x - 1/3

y = (2/3)*x + 5/3

Now let's assume that we apply a translation to the first line, that has points of the form (x,  (2/3)*x - 1/3), such that we want to get points of the form:

(x, (2/3)*x + 5/3).

Then we must have:

T(a, b)(x,  (2/3)*x - 1/3) = (x + a,  (2/3)*x - 1/3 + b) = (x, (2/3)*x + 5/3).

Then we need to solve:

(x + a,  (2/3)*x - 1/3 + b) = (x, (2/3)*x + 5/3).

This means that:

x + a = x

(2/3)*x - 1/3 + b = (2/3)*x + 5/3

From the first equation, we can see that a = 0

Now we can solve the second one to find the value of b.

(2/3)*x - 1/3 + b = (2/3)*x + 5/3

subtracting (2/3)*x in both sides, we get:

-1/3 + b = 5/3

b = 5/3 + 1/3

b = 6/3 = 2

b = 2

Then the vector translation is:

T(0, 2)

So it moves the whole line 2 units upwards.

7 0
3 years ago
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