Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
The formula of a continuous compound interest is
A=p e^rt
A the balance?
P present value 750
E constant
R interest rate 0.08
T time 5 years
A=750×e^(0.08×5)
A=1,118.87
I dont quite undeerstand but the gcf for both are..., if that helps is 4 because
30:2*2*2*2*2
22:2*2 5
There is 60 seconds in 1 minute
600/60 = 10
10 minutes is your answer
hope this helps
