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olga55 [171]
3 years ago
14

Suppose that your tuition to attend college is $24,000 per year and you spend $8,000 per year on room and board. If you were wor

king full time, you could earn $30,000 per year. What is your opportunity cost of attending college for one year? $32,000 $38,000 $54,000 $62,000
Business
1 answer:
yawa3891 [41]3 years ago
6 0

Answer:

$30,000

Explanation:

Opportunity cost or implicit is the cost of the option forgone when one alternative is chosen over other alternatives.

In order to attend college, i would have to give up working. My opportunity cost is what i would have earned if i was working. This is $30,000.

Explicit cost is the cost actually incurred in carrying out an activity. Here, it is the total amount expended in attending college = $24,000 + $8,000 = $32,000

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D is the answer!!!!!Hope this helped 
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3 years ago
Frankie's Chocolate Co. reports the following information from its sales budget: Expected Sales: July $ 100,000 August 120,000 S
Temka [501]

Answer:

<u>Total cash receipts = 123,000</u>

Explanation:

September cash receipts:

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70% of August sales (previous month)

70% of 120,000 = 84,000

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Note: We are asked for september collection from sales:

30% of september is in cash, so are colected instantly.

Then the remaining, which are credit sales are canceled in the following month.

So the credit sales of August are collected in the following month, which is september. That's why it is included in the calculation.

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7 0
4 years ago
Suppose you know that a company’s stock currently sells for $55 per share and the required return on the stock is 8 percent. Y
inysia [295]

Answer:

Dividend per share $ 2.16

Explanation:

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Dividend yield = Capital gains yield

Div yield 0.08 / 2 = 0.04

Next year dividend:

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$ 55 x 0.04  =  $2.2

<u>Current dividend:</u>

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8 0
4 years ago
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John is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than u
Vinil7 [7]

Answer:

0.0042 is the probability of the stick's weight being 2.33 oz or greater.  

Explanation:

We are given the following information in the question:

Mean, μ = 1.75 oz

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We are given that the distribution of drumsticks is a bell shaped distribution that is a normal distribution.

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z_{score} = \displaystyle\frac{x-\mu}{\sigma}

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Calculation the value from standard normal z table, we have,  

P(x > 2.33) = 1 - 0.9958 =0.0042= 0.42\%

0.0042 is the probability of the stick's weight being 2.33 oz or greater.

6 0
3 years ago
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