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4 years ago

A pile driver drops from a height of 35 meters

Physics

2 answers:

alexgriva [62]4 years ago

5 0

Answer:

26.19 m/s

Explanation:

The gravitational potential energy of the driver would convert to the kinetic energy at the bottom.

$mg h = 0.5 mv^2$

Where, m is the mass, v is the speed, h is the height and g is the acceleration due to gravity.

Given,

h = 35 m

$v = \sqrt {2gh}= \sqrt {2\times 9.8\times 35} =26.19 m/s$

MakcuM [25]4 years ago

3 0

It is good so what is what’s they says didn’t. Fiend. Diehard d fish

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3 years ago

Will the net force be greater or lesser for objects with greater mass?

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The net force will be lesser for objects with greater mass

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3 years ago

A thin uniform rod (mass = 0.53 kg) swings about an axis that passes through one end of the rod and is perpendicular to the plan

gladu [14]

Answer:

(a) L = 0·73 m

(b) 4·39 × $10^{-3}$ J

Explanation:

(a) From the figure, consider the torque about the point where the rod is attached because if we consider another point then there will be hinge forces acting on the rod at the point of attachment

Let L m be the length of the rod and β be the angle between the rod and the vertical

Let α be the angular acceleration of the rod

As the force of gravity acts at the centre so from the figure, the torque about the point of attachment will be 0·53 × g ×(L ÷ 2) ×sinβ

Assuming that the value of amplitude of this oscillation to be small

As torque = moment of inertia × angular acceleration

0·53 × g ×(L ÷ 2) ×sinβ = ((0·53 × L²) ÷ 3) × α (∵ moment of inertia of the rod from the point of attachment)

<h3>For small oscillations, α = ω² × β</h3>

After substituting the value of α and solving we get

ω = √((3 × g) ÷ (2 × L))

Time period = (2 × π) ÷ ω = (2 × π) ÷ √((3 × g) ÷ (2 × L))

∴ (2 × π) ÷ √((3 × g) ÷ (2 × L)) = 1·4

Substituting the value of g as 9·8 m/s² and solving we get

L = 0·73 m

(b) At the maximum amplitude condition the velocity will be 0 and potential energy will be maximum and maximum kinetic energy will be attained at the lowest point and hinge forces will not do work as the point of attachment is not moving

∴ Taking the reference for finding the potential energy as the lowest point

<h3>Maximum potential energy = Maximum kinetic energy </h3><h3>As total energy is constant, since there is no dissipative force</h3>

Maximum potential energy = (0·53 × g × L ×(1 - cosβ)) ÷ 2 (∵ increment in height is (L × (1 - cosβ)) ÷ 2

∴ Maximum potential energy = (0·53 × g × L ×(1 - cosβ)) ÷ 2 After substituting the value we get

Maximum potential energy = 4·39 × $10^{-3}$ J

∴ Maximum kinetic energy = 4·39 × $10^{-3}$ J

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3 years ago

Which item(s) would be sufficient to make a circuit?

masya89 [10]

Explanation :

A circuit is the representation of the path of the flow of current. The circuit can be either closed or open.

When the switch is off the circuit is closed circuit and when the switch is not connected the circuit is open.

The items that are sufficient to make a circuit are as follows :

Voltage source like a battery.
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Other components can be ammeter, voltmeter, ac source, variable resistors etc.

7 0

3 years ago

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the maximum normal force a pilot can withstand is about eight times his weight. What is the maximum radius of curvature that a j

neonofarm [45]

Complete Question

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Answer:

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