Answer:
The total energy to break all the bonds in 1 mole of 1-propanol, C₃H₈O, is 4411 kJ/mol
Explanation:
We note that propanol, C₃H₈O is also known as 1-propanol is written as follows;
CH₃CH₂CH₂OH which gives
CH₃-CH₂-CH₂-OH
Hence, the total number of bonds are;
C-H Bonds = 3 + 2 + 2 = 7
C-O Bonds = 1
O-H Bond = 1
C-C Bonds = 2
The bond energies are as follows;
C-H Bonds = 413 kJ/mol
C-O Bonds = 358 kJ/mol
O-H Bond = 468 kJ/mol
C-C Bonds = 347 kJ/mol
Energy required to break the bonds in 1-propanol is therefore;
C-H Bonds = 413 kJ/mol × 7 = 2,891 kJ/mol
C-O Bonds = 358 kJ/mol × 1 = 358 kJ/mol
O-H Bond = 468 kJ/mol × 1 = 468 kJ/mol
C-C Bonds = 347 kJ/mol × 2 = 694 kJ/mol
The total energy to break all the bonds in 1 mole of 1-propanol = 4411 kJ/mol.
Answer:
its polar end mixes with the water so it can be washed away
Explanation:
just did the tests
a p e x
Answer:
The energy of the products is less than the energy of the reactants, so energy is released into the surrounding environment.
All u do is divide the mass by the volume so 85.4/7 which is 12.2
Answer:
The two products of this reaction, Sodium Chloride and Potassium Sulfate, are both soluble in water, hence, there's no precipitate formed from this reaction.
Explanation:
Sodium sulfate is Na₂So₄
Potassium Chloride is KCl
When they both react, theres a double displacement where ions and radicals are exchanged
Na₂SO₄ + KCl → NaCl + K₂SO₄
The products are
NaCl - Sodium Chloride
K₂SO₄ - Potassium Sulfate
The two products are soluble in water, hence, there's no precipitate formed from this reaction.
And we would need numerical values of the number of moles of the two reactants mixed to obtain the number of moles of products formed and then the number of molecules from Avogadro's constant.
Hope this Helps!!!
