The kb of hypochlorous acid is 3. 0×10^–8 at 26. 0 C. What is the percent of ionization of hypochlorous?
1 answer:
The acid dissociation constant (Ka) defines the difference between a weak and a strong acid. The % ionization of hypochlorous acid is 0.14%.
<h3>What is the acid dissociation constant?</h3>The acid dissociation constant is used to define the ionization constant of an acidic substance. It gives the quantitative measurement of the strength.
The ICE table is attached to the image below.
The acid dissociation constant (Ka) for the reaction is,
Ka = [H⁺][ClO⁻] ÷ [HClO]
= a² ÷ (0.015 - a)
= 3.0 x 10⁻⁸
Now, a² + 3.0 x 10⁻⁸ a - 4.5 × 10⁻¹⁰ = 0
So, a = 2.210 × 10⁻⁵
Solving further,
[H+] = a = 2.210 × 10⁻⁵ M
The percent ionization is calculated as,
[H+] ÷ [HClO] × 100
= 2.210 × 10⁻⁵ M ÷ 0.015 × 100
= 0.14 %
Therefore, 0.14 % is the percentage of hypochlorous ionization.
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Your question is incomplete, but most probably your full question was, The ka of hypochlorous acid (HClO) is 3.0 x 10⁻⁸ at 25.0°C. What is the % of ionization of hypochlorous acid in a 0.015 aqueous solution of HClO at 25.0C?
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Answer : The new pressure if the volume changes to 560.0 mL is, 280 mmHg
Explanation :
According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.
or,
where,
= initial pressure = 560.00 mmHg
= final pressure = ?
= initial volume = 280 mL
= final volume = 560.0 mL
Now put all the given values in the above formula, we get:
Therefore, the new pressure if the volume changes to 560.0 mL is, 280 mmHg