131.88 or jus do radius times 2 so 21+ 21 = 42.
42 x pi(3.14) = 131.88
        
             
        
        
        
Perimeter is adding all 4 sides together.
To find the length and width divide total perimeter by 2:
21 / 2 = 10.5
We now know the length of 1 side and the width of 1 side need to equal 10.5.
Since the original piece was a square we also know the width needs to equal 1/2 of the length.
So we have L + 1/2L = 10.5
Add the common terms 1 L + 1/2 L = 1 and 1/2 L
To Find L divide 10.5 by 1-1/2, which equals 7
To find the width subtract 7 from 10.5, which equals 3.5
So the paper is now 3.5 inches by 7 inches.
 
        
             
        
        
        
Hi there!
So we are given that:-
- tan theta = 7/24 and is on the third Quadrant.
In the third Quadrant or Quadrant III, sine and cosine both are negative, which makes tangent positive. 
Since we want to find the value of cos theta. cos must be less than 0 or in negative.
To find cos theta, we can either use the trigonometric identity or Pythagorean Theorem. Here, I will demonstrate two ways to find cos.
<u>U</u><u>s</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>I</u><u>d</u><u>e</u><u>n</u><u>t</u><u>i</u><u>t</u><u>y</u>

Substitute tan theta = 7/24 in.

Evaluate.

Reminder -: 

Hence,

Because in QIII, cos<0. Hence,

<u>U</u><u>s</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>P</u><u>y</u><u>t</u><u>h</u><u>a</u><u>g</u><u>o</u><u>r</u><u>e</u><u>a</u><u>n</u><u> </u><u>T</u><u>h</u><u>e</u><u>o</u><u>r</u><u>e</u><u>m</u>

Define c as our hypotenuse while a or b can be adjacent or opposite.
Because tan theta = opposite/adjacent. Therefore:-

Thus, the hypotenuse side is 25. Using the cosine ratio:-

Therefore:-

Because cos<0 in Q3.

Hence, the value of cos theta is -24/25.
Let me know if you have any questions!
 
        
             
        
        
        
For this, you've just got to add 2 hours to 8:10, 8+2=10.
Therefore, school would begin at 10:10am if there was a two hour delay :)