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MissTica
4 years ago
9

How to solve trigonometry problems when x is on the bottom of the fraction. Example sin27=34/x

Mathematics
2 answers:
ad-work [718]4 years ago
8 0
Multiply both sides by x to cancel the x on bottom

x sin 27=34

Then divide both sides by sin 27

x = 34 / sin 27

So, x = 75.89
Dmitriy789 [7]4 years ago
5 0
  sin(27) = ³⁴/ₓ
xsin(27) = x(³⁴/ₓ)
xsin(27) = 34
 sin(27)  sin(27)
           x = 74.891435

To solve trigonometry problems when x is on the bottom of the fraction, you have to multiply it each by x and divided it each by the trigonometric problem to find the value of x.

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Solve the quadratic equation by taking the square root of (x+5)^2=16
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Hi okay i’m gonna write the explanation i hope you give me a brilliant if you think I’m deserving it thank you

(x-5)2=16


The first step you can take to solve this quadratic is to take the square root of both sides of the equation.

√[(x-5)2]=√(16)

When you take the square root of a term that is square it equals what is inside the parentheses.

So on the left side, you have x-5

On the right side, you are what we call "forcing" the square root. When this happens, you need to put ±. Why? Good question. When you square a negative number it positive; when you square a positive number it is also positive.

The √16 = ±4

So now we have;
x-5=±4

What do you do with that?
You make two separate equations.

x-5=4 and x-5=-4
x=9 x=1


Let's check our answers

x=9

(x-5)2=16
(9-5)2=16
42=16
16=16 it checks

x=1

(x-5)2=16
(1-5)2=16
(-4)2=16
16=16 it also checks


ANSWER: x=9 and x=1
5 0
2 years ago
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Step-by-step explanation:

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