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Alenkinab [10]
4 years ago
12

Angle Sum of a 1502 Sided Polygon *

Mathematics
1 answer:
notsponge [240]4 years ago
5 0

Answer:

270,000^o

Step-by-step explanation:

we know that

The formula to calculate the sum of the interior angles of a polygon is equal to

S=(n-2)180^o

where

n is the number of sides of polygon

In this problem we have

n=1,502\ sides

substitute in the formula

S=(1,502-2)180^o

S=(1,500)180^o

S=270,000^o

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Ganezh [65]

Correlation coefficients are expressed by a number between -1 and 1.

If the value is -1 or 1 it indecates a perfect (negative and positive) correlation.

If the value is 0 indicates null correlation.

As the correlation value for you data set is -0.833 it is very close to the -1. It indicates a good correlation in the data. Then, the value you predicted is reasonably close to the actual value.

6 0
2 years ago
Estimate the square root of 25<br> to the nearest integer
andrey2020 [161]
The square root of 25 is 5. 
6 0
3 years ago
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Write the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x y = -5.
Alik [6]
Y=2x-5 because parallel means keep the slope the same and the formula is y=mx+b b is y and y is -5 so your answer is y=2x-5
6 0
3 years ago
2ᵃ = 5ᵇ = 10ⁿ.<br> Show that n = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bab%7D%7Ba%20%2B%20b%7D%20" id="TexFormula1" titl
11Alexandr11 [23.1K]
There are two ways you can go about this: I'll explain both ways.
<span>
</span><span>Solution 1: Using logarithmic properties
</span>The first way is to use logarithmic properties.

We can take the natural logarithm to all three terms to utilise our exponents.

Hence, ln2ᵃ = ln5ᵇ = ln10ⁿ becomes:
aln2 = bln5 = nln10.

What's so neat about ln10 is that it's ln(5·2).
Using our logarithmic rule (log(ab) = log(a) + log(b),
we can rewrite it as aln2 = bln5 = n(ln2 + ln5)

Since it's equal (given to us), we can let it all equal to another variable "c".

So, c = aln2 = bln5 = n(ln2 + ln5) and the reason why we do this, is so that we may find ln2 and ln5 respectively.

c = aln2; ln2 = \frac{c}{a}
c = bln5; ln5 = \frac{c}{b}

Hence, c = n(ln2 + ln5) = n(\frac{c}{a} + \frac{c}{b})
Factorise c outside on the right hand side.

c = cn(\frac{1}{a} + \frac{1}{b})
1 = n(\frac{1}{a} + \frac{1}{b})
\frac{1}{n} = \frac{1}{a} + \frac{1}{b}

\frac{1}{n} = \frac{a + b}{ab}
and thus, n = \frac{ab}{a + b}

<span>Solution 2: Using exponent rules
</span>In this solution, we'll be taking advantage of exponents.

So, let c = 2ᵃ = 5ᵇ = 10ⁿ
Since c = 2ᵃ, 2 = \sqrt[a]{c} = c^{\frac{1}{a}}

Then, 5 = c^{\frac{1}{b}}
and 10 = c^{\frac{1}{n}}

But, 10 = 5·2, so 10 = c^{\frac{1}{b}}·c^{\frac{1}{a}}
∴ c^{\frac{1}{n}} = c^{\frac{1}{b}}·c^{\frac{1}{a}}

\frac{1}{n} = \frac{1}{a} + \frac{1}{b}
and n = \frac{ab}{a + b}
4 0
3 years ago
−6(x+7)=−4x−2 how many solutions
yaroslaw [1]

Answer: There is one solution, -20

Step-by-step explanation:

-6(x+7)=-4x-2\\\\Distribute\\\\-6x-42=-4x-2\\\\Add(6x)\\\\-42=2x-2\\\\Add(2)\\\\-40=2x\\\\x=-20

There is one solution, -20

Hope it helps <3

8 0
3 years ago
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