4a^4 -2b^2 +40
a=2
b=7
4(2)^4 -2(7)^2 +40
PEMDAS is what your gonna use to solve this you go from right to left
First is P which is parentheses which is none
second is E which stands for exponents
4(32)-2(49)+40
now MD multiply or divide
128-98+40
now add or subtract
30+40
last one
70 this is your answer i hope
Step-by-step explanation:
only 10 and 12. luck to you
Answer:
14
Step-by-step explanation:
Arithmetic expressions are best evaluated using a reliable calculator. The Google calculator always follows the Order of Operations, so can give you a good answer to such questions.
(1/4)^-2 - (5^0)(2)(1^-1)
= 16 - (1)(2)(1) . . . . evaluate the exponents first
= 16 -2 . . . . . . . . . evaluate the product next
= 14 . . . . . . . . . . . finally, evaluate the sum
___
The rule of exponents is ...
a^-b = 1/(a^b)
150 miles/hour
Hope this helps!
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-7
We can find this by subtracting the first term by the second
So 43-37=7
If we subtract the second by the third, we also get 7 and so on
Since the sequence is decreasing, that means it has to be a negative value that it is going by.
So the pattern is -7