Point slope form is
y-y1=m(x-x1)
where slope=m
and (x1,y1) is a given point
slope=(y2-y1)/(x2-x1)
slope=(6-7)/(-8-(-5))=-1/(-8+5)=-1/-3=1/3
pick any point
(x,y)
(-5,7)
y-7=1/3(x+5) or
y-6=1/3(x+8)
Answer:
Radius is half the diameter of a circle
Step-by-step explanation:
If the diameter was 6, then the radius is 3
Answer:
Step-by-step explanation:
Let
y ----> the length of the board
x ----> the width of the board
we know that
----> equation A
The area of the board is
----> equation B
substitute equation A in equation B
The quotient is x^3 + 4x^2 -x + 1.
Solution:
By polynomial grid division, we start by the divisor 3x + 10 placed on the column headings.
3x 10
x^3 3x^4
We know that 3x^4 must be in the top left which means that the first row entry must be x^3. So the row and column multiply to 3x^4. We use this to fill in all of the first row, multiplying x^3 by the terms of the column entries.
3x 10
x^3 3x^4 10x^3
4x^2
We now got 10x^3 though we want 22x^3. The next cubic entry must then be 12x^3 so that the overall sum is 22x^3.
3x 10
x^3 3x^4 10x^3
4x^2 12x^3
Now we have 40x^2, so the next quadratic entry must be -3x^2 so that the overall sum is 37x^2.
3x 10
x^3 3x^4 10x^3
4x^2 12x^3 40x^2
-x -3x^2 -10x
This time we have -10x, so the next linear entry must be 3x so that the overall sum is 7x.
3x 10
x^3 3x^4 10x^3
4x^2 12x^3 40x^2
-x -3x^2 -10x
1 3x 10
The bottom and final term is 10, which is our desired answer. Therefore, we can now read the quotient off the first column:
3x^4+22x^3+37x^2-7x+10 / 3x + 10 = x^3 + 4x^2 -x + 1
Answer: 7
Step-by-step explanation:
First set up your equation 40+21x=187
Subtract 40 from each side 187-40=147 40-40=0 Bring down your 21x than divide 147 by 21. 147÷21=7
