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Oksi-84 [34.3K]
3 years ago
11

How do you simplify rational expressions?​

Mathematics
1 answer:
deff fn [24]3 years ago
7 0

The simplification of rational expressions is explained

<u>Solution:</u>

Rational expressions are fractions that have a polynomial in the numerator, denominator, or both.

Rational expressions contain variables, they can be simplified in the same way that numerical fractions are simplified.

<em><u>Steps to simplify rational expressions:</u></em>

Let us see it with an example:

\frac{3 x^{2}-3 x}{3 x^{3}-6 x^{2}+3 x}

1) Look for factors that are common to the numerator & denominator

\frac{3 x(x-1)}{3 x\left(x^{2}-2 x+1\right)}

2) 3x is a common factor to the numerator & denominator. Note that it is clear that x ≠0

3) Cancel the common factor

\frac{x-1}{x^{2}-2 x+1}

4) If possible, look for other factors that are common to the numerator and denominator

\frac{x-1}{(x-1)(x-1)}

5) After cancelling, you are left with \frac{1}{(x-1)}

6) The final simplified rational expression is valid for all values of "x" except 0 and 1

We have to follow the same procedure for any rational expression.

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Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

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