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2 years ago

13

Explain how you know that square root of 30 is between 5 and 6

1 answer:

EleoNora [17]2 years ago

5 0

The square root of 36 is 6 and the square root of 25 is 5. 30 is in between 36 and 25 so the square root should be between 6 and 5.

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A formula for finding P, the perimeter of a rectangle, is P = 2l + 2w, where l is the length of the rectangle, and w is its widt

Varvara68 [4.7K]

Answer:

P=30cm

Step-by-step explanation:

So the formula there is to find the Perimeter of the rectangle, so we are going to use it!

Using Substitution:

$A=2L+2W\\A=2(10)+2(5)\\A=20+10\\A=30$

Hope this helps!

Stay Safe!

4 0

3 years ago

Matteo is adjusting a satellite because he finds it is not focusing the incoming radio waves perfectly. The shape of his satelli

natka813 [3]

Answer: (1.5, 0)

Step-by-step explanation:

Given : The shape of his satellite can be modeled by $y^2=6x$ where x and y are modeled in inches.

Now,the given equation $y^2=6x$ is a equation of parabola.

Here, coefficient of x is positive, hence the parabola opens rightwards.

On comparing this equation with standard equation $x^2=4mx$ , we get

$4m=6\\\Rightarrow\ m=\frac{6}{4}=1.5$

In standard equation, coordinates of focus=(m,0)

Thus for given equation coordinates of focus=(1.5,0)

4 0

2 years ago

Read 2 more answers

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

How do you find the width of a rectangle when the perimeter is given?

ololo11 [35]

Usually you are given more information about the rectangle such as distance of length in terms of width.

You know that the formula for perimeter is

P=2(l+w)

Substitute p and the other values to find width.

Hope I helped :)

4 0

3 years ago

An airplane travels 500 miles in 2 hours. What is the airplane's speed in feet per second? How to do step by step.

Slav-nsk [51]

Here you go..............

3 0

2 years ago