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Nastasia [14]
3 years ago
7

I need some help with geometry.

Mathematics
2 answers:
motikmotik3 years ago
7 0

Answer:

x = 17, angle 1 and 2 = 45

Step-by-step explanation:

Dmitry_Shevchenko [17]3 years ago
7 0
I think x=17 but i’m not sure
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Find the slope of the line that passes through<br> (10, 1) and (6,2)
Daniel [21]

Answer:

m=-1/4

Step-by-step explanation:

2-1/6-10=1/-4

-1/4 is the slope

7 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK​
Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = ∠KLM
  • A = LN = 8
  • H = KL = 15.2

\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

6 0
2 years ago
Which expression shows the sum of the polynomials with like terms grouped together? (8x+3z-8z^2)+(4y-5z)
Andrews [41]
It’s (-8z^2 +8x +4y -2z)

Hope it helps
3 0
3 years ago
What is the ratio of 24 packs 2 for $9
topjm [15]
24 cans = 2 cans
$x                $9
2x= 260
x=180
24 cans/ $108= 2 cans/ $9
5 0
3 years ago
A sample size of n = 64 is drawn from a population whose standard deviation is o = 5.6.
AlekseyPX

Answer:

The margin of error for a 99% confidence interval for the population mean is 1.8025.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem:

\sigma = 5.6

So

M = 2.575*\frac{5.6}{\sqrt{64}} = 1.8025

The margin of error for a 99% confidence interval for the population mean is 1.8025.

5 0
3 years ago
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