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Firdavs [7]
3 years ago
5

Does this graph show a function? Explain how you know.

Mathematics
1 answer:
DanielleElmas [232]3 years ago
6 0

Answer:

yes

Yes; the graph passes the vertical line test.

Step-by-step explanation:

if it were a graph of a circle it would not pass

the vertical line test because the vertical line would touch at least 2 points

graph is probably a cubic function

something like

y = x^3-4x+6

You might be interested in
Find the coordinates of the intersection of the diagonals of the parallelogram with the vertices W(−2, 5), X(2, 5), Y(4, 0),
emmasim [6.3K]

Using the midpoint formula, the coordinates of the intersection of the diagonals of the parallelogram is: (1, 2.5).

<h3>What are Diagonals of a Parallelogram?</h3>

The diagonals of a parallelogram bisect each other, therefore, the coordinates of their intersection can be determined using the midpoint formula, which is: M(\frac{x_2 + x_1}{2}, \frac{y_2 + y_1}{2}).

A diagonal is XZ.

X(2, 5) = (x1, y1)

Z(0, 0) = (x2, y2)

Plug in the values

M(\frac{0 + 2}{2}, \frac{0 + 5}{2})

= (1, 2.5).

Learn more about the diagonals of a parallelogram on:

brainly.com/question/12167853

#SPJ1

7 0
2 years ago
Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps
Firdavs [7]
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4

Therefore, for the two expressions to be conjugates, we must satisfy the two conditions. 

Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the 

   x²y = -4 ... (I)

Condition 2: Real parts are the same

   x² + y = -3 ... (II)

We have a system of equations since both conditions must be satisfied

   x²y = -4 ... (I)
   x² + y = -3 ... (II)

We can rearrange equation (II) so that we have

   y = -3 - x² ... (II)

Substituting into equation (I)

   x²y = -4 ... (I)
   x²(-3 - x²) = -4
   -3x² - x⁴ = -4
   x⁴ + 3x² - 4 = 0
   (x² + 4)(x² - 1) = 0
   (x² + 4)(x-1)(x+1) = 0

Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

Solve for y:

   y = -3 - x² ... (II)
   y = -3 - (±1)²
   y = -3 - 1
   y = -4

So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:

   -3 + ix²y 
   = -3 + i(±1)²(-4)
   = -3 - 4i

   x² + y + 4i
   = (±1)² - 4 + 4i
   = 1 - 4 + 4i
   = -3 + 4i

They result in conjugates
4 0
3 years ago
Read 2 more answers
Two dice are tossed. The probability that the total score is a prime number is:​
andrew11 [14]

Step-by-step explanation:

50/50 it's random I think but I learned that in science

8 0
3 years ago
Read 2 more answers
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Alexxx [7]
Why u have so much letters lol what u need help on
4 0
3 years ago
7 line tshirt company manufactures t-shirts and sells them online.The company has a model where the cost C, in dollars to make x
bonufazy [111]

Answer:

The company must sell at least 2 shirts to break even.

Step-by-step explanation:

Cost:

The cost is given by the following equation:

C = \frac{40}{30x+20} + 20 = \frac{4x}{3} + 20

Revenue:

The revenue is given by the following equation:

R = 15x

How many t shirts must the company sell to break even?

Breakeven point is when the revenue is the same as the costs. So

\frac{4x}{3} + 20 = 15x

15x - \frac{4x}{3} = 20

\frac{45x}{3} - \frac{4x}{3} = 20

Multiplying everything by 3

45x - 4x = 60

41x = 60

x = \frac{60}{41} = 1,...

Since you cant make a decimal value of shirts

The company must sell at least 2 shirts to break even.

[

7 0
3 years ago
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