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Goshia [24]
3 years ago
8

translated 3 units right and 2 units up. Then it is rotated 270 counterclockwise about the origin resulting in quadrilateral PQR

S. How does the perimeter of quadrilateral ABCD compare with the perimeter of PQRS? Explain

Mathematics
1 answer:
Daniel [21]3 years ago
4 0

Because the shape is not undergoing a dilation, the perimeter of the original image and the new image is the same. The only thing that is changing is the placement of the original figure.


I hope this helps! :)

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Answer:

assuming only positive integers, the answer is 1

Step-by-step explanation:

the smallest number that you can get by adding is:

  • start with 0
  • then add 1 = 1
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  • add another 1 = 3
  • add another 1 = 4
  • add another 1 = 5

but you can also multiply, and anything multiplied by 0 is 0:

  • start with 0
  • multiply by 2 = 0
  • multiply by 2 = 0
  • multiply by 2 = 0
  • multiply by 2 = 0
  • multiply by 2 = 0

The question does not say that we need to do any specific calculation, it only gives us 2 options and we can choose them as many times as we want.

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Answer:

Can I please have more details on what your question is?

Step-by-step explanation:

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Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

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