1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
Answer: It is D
Step-by-step explanation:
5, 10, 15, 20, 5n, 470
You just need to multiply the value by 5.
Answer: D (1,0): (6,5); (36,10): (216,15)
Step-by-step explanation:
Because 1x6=6 0+5=5
6x6=36 5+5=10 ect.
Answer:
answer is c Hope this helps
Step-by-step explanation:
