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3 years ago

Log(14/3) + log(11/5) - log(22/15) = log _

Mathematics

2 answers:

victus00 [196]3 years ago

5 0

Answer:

log 7

Step-by-step explanation:

We have to find the value of the logarithmic expression

Log(14/3) + log(11/5) - log(22/15)

We know the formula

log a + log b = log (ab)

Using this formula, we have

log(14/3) + log(11/5) - log(22/15)

=log ( 14/3 × 11/5) - log(22/15)

= log (154/15)- log(22/15)

Now, use the formula log a - log b = log (a/b)

= log (154/15×15/22)

On simplifying, we get

= log 7

Thus, the shoplifted form is log 7

Anika [276]3 years ago

3 0

= log ( 14/3 * 11/5 ) / (22/15) = log 7 = 0.8451

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2 years ago

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Damm [24]

Answer:

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Step-by-step explanation:

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2 years ago

Let theta be an angle in quadrant 2 such that cos theta =-3/4. Find the exact values of csc theta and cot theta.

Anna35 [415]

Step-by-step explanation:

Since $cos(\theta) = -\frac{3}{4}$ we can get some information from this. First of all $cos(\theta)$ is defined as $\frac{adjacent}{hypotenuse}$ . So the adjacent side is 3 and the hypotenuse is 4. Using this we can find the opposite side to find $sin(\theta)$ to calculate csc and cot of theta. So using the Pythagorean Theorem we can solve for the missing side. Also I forget to mention we have to calculate the sign of the adjacent side and the hypotenuse. Since you're given that the angle is in quadrant 2, that means the x-value is going to be negative, and the y-value is going to be negative. And the x really represents the adjacent side and the y represents the opposite. So the adjacent side is what's negative. and the opposite is positive

Pythagorean Theorem:

$a^2+b^2=c^2$

$(-3)^2 + b^2 = 4^2$

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$b = \sqrt{7}$

So now we can calculate $sin(\theta)$ .

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Now to calculate the exact value of csc you simply take the inverse. This gives you $csc(\theta)=\frac{4}{\sqrt{7}}$ . Multiplying both sides by sqrt(7) to rational the denominator gives you $\frac{4\sqrt7}{7}$ .

Now to calculate cot(theta) you find the inverse of tan. Tan is defined as $tan(\theta) = \frac{sin(\theta)}{cos(\theta)}$ . So all you do is take the inverse which is $cot(\theta) = \frac{cos(\theta)}{sin(\theta)}$ .