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3 years ago

How Extreme Programming addresses Software Testing andevolution ?

Computers and Technology

1 answer:

kumpel [21]3 years ago

6 0

Answer:

Extreme programming is a software development technique which is used to enhance software quality and it's response to ever changing customer requirements.

Testing

Testing is main focus in extreme programming.Extreme programming addresses testing in a way that if a minute testing can eliminate a bit of flaws, extensive testing can terminate a lot of flaws.

Evolution in Extreme programming is like this:-

Coding:-First programmers will code the problem.

Testing :- Testing is done to remove flaws.

Listening:- Programmers must listen to the customers to what they need.

Designing:-Then design according to the customer needs.

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Technician A says that the reserve rating of a battery is the amount of steady current that a fully charged battery can supply f

Andre45 [30]

Answer:

Neither A nor B

Explanation:

<em>Reserve capacity</em> is the number of minutes that a new, fully charged battery can discharge continuously and maintain a terminal voltage equal to or greater than 1.75 volts per cell.

<em>An ampere-hour </em>is an electric charge unit and its abbreviation is Ah.

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3 years ago

Which scenario depicts an ethical workplace practice by a business owner

viva [34]

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3 years ago

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Any anime weebs wanna talk

erastova [34]

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Sowwy, it's not Me!

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Bermuda Triangle

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2 years ago

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Given the following adjacency matrix, what is the approximate rank vector after one iteration of the power iteration method (use

ValentinkaMS [17]

Note: The matrix referred to in the question is: $M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]$

Answer:

a) [5/18, 5/18, 4/9]'

Explanation:

The adjacency matrix is $M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]$

To start the power iteration, let us start with an initial non zero approximation,

$X_o = \left[\begin{array}{ccc}1\\1\\1\end{array}\right]$

To get the rank vector for the first Iteration:

$X_1 = MX_0$

$X_1 = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]\left[\begin{array}{ccc}1\\1\\1\end{array}\right] \\\\X_1 = \left[\begin{array}{ccc}5/6\\5/6\\4/3\end{array}\right]\\$

Multiplying the above matrix by 1/3

$X_1 = \left[\begin{array}{ccc}5/18\\5/18\\4/9\end{array}\right]$

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3 years ago

Point giveaway and brainliest

melamori03 [73]

Thank you, pal!

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3 years ago

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