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Vinvika [58]
3 years ago
5

you want to create a box that can hold at the very longest a 4in object. find the dimensions of a box that will work

Mathematics
2 answers:
ser-zykov [4K]3 years ago
5 0

If you were working with a flat rectangle and you were given the diagonal,
you'd want to use the Pythagorean theorem to choose two sides whose
squares would add up to the square of the diagonal.

It works exactly the same with a 3-D box.  We need three dimensions for
the box, whose squares add up to the square of the diagonal between
opposite corners.  That's (4)² = 16.

So (L)² + (W²) + (H²) = 16 . From there, you're completely free to pick any
numbers you want, just as long as their squares add up to 16.  There are
an infinite number of possibilities.  Here are a few:

1 x 1 x √14

1 x 2 x √11

2 x 2 x √8

2 x 3 x √3

1 x 3 x √6


Veronika [31]3 years ago
4 0
4×4×4 hope i help have a great day
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Answer:

<em>B. 30 degrees</em>

Step-by-step explanation:

Find the diagram attached

From the diagram:

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(4/3)x°+20 = 2x°

multiply through by 3:

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4x°-6x° = -60

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x°= -60/-2

<em>x° = 30°</em>

Hence the value of x is 30 degrees

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3 years ago
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lubasha [3.4K]

Answer:

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2 years ago
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Answer:

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