Let the width be x.
Length is 8 feet more than width. Length = x + 8
Area = x(x + 8)
width increased by 4, that is, (x + 4)
Length decreased by 5, (x + 8 - 5) = (x + 3)
Area = (x + 4)(x +3)
Area remains the same
x(x + 8) = (x+4)(x +3)
x² + 8x = x(x +3) + 4(x +3)
x² + 8x = x² +3x + 4x +12
x² + 8x = x² +7x +12 Eliminate x² from both sides
8x = 7x + 12
8x - 7x = 12
x = 12
Dimensions of original rectangle : x, x + 8
12, 12 +8 = 12, 20
Original rectangle is 20 feet by 12 feet
Answer
-1(3a-2)
Step-by-step explanation:
Answer:
-4f-5
Step-by-step explanation:
M
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h
w
a
y
Answer:
The pair (0,3) is not a solution to the equation
Step-by-step explanation:
This can be proved by simply replacing the x and y variables in the equation by the x and y values of the pair, and checking if the equation renders a true statement:
By replacing x and y with their values in the pair (0,3), that is x=0 and y=3, in the equation y = 5 - 2x we get:
3 = 5 - 2 (0)
3 = 5 - 0
3 = 5
which is NOT a true statement.
On the other hand, the other two pairs (2,1) and (1,3) render true statements:
1 = 5 - 2 (2)
1 = 5 - 4
1 = 1
and
3 = 5 - 2 (1)
3 = 5 - 2
3 = 3