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umka2103 [35]
4 years ago
8

Please need some help on this

Mathematics
2 answers:
elena-14-01-66 [18.8K]4 years ago
4 0

All you have to do is simplify the equation, and then isolate g.

-5 + 7g = 3g + 9                       add 5 to both sides to isolate 7g

7g = 3g + 14                             subtract 3g from both sides to isolate g

4g = 14                                     divide both sides by 4 to isolate g

g = 3.5

The answer is D- 3\frac{1}{2}


Dafna11 [192]4 years ago
3 0
This is the work. the answer is g=1.4

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At Picture Perfect Pizza the price for 2 slices of pizza is $3.00. At Pizza Outpost
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Answer:

You will save $2 if you buy from Picture Perfect Pizza instead of Pizza Outpost.

Step-by-step explanation:

First we need to find the unit rate of each pizza from each pizza place.

Picture Perfect Pizza: $3÷2 = $1.50

Pizza Outpost: $7÷4 = $1.75

Picture Perfect Pizza: $1.5 * 8 = $12

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3 years ago
Question 22 Petrolyn motor oil is a combination of natural oil and synthetic oil. It contains 8 liters of natural oil for every
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Answer:

897 liters

Step-by-step explanation:

The motor oil is composed of 8 liters of natural oil and 5 liters of synthetic oil. This means there is a ratio of 8/5. We have 552 liters of natural oil to y liters of synthetic. This is the ratio 552/y. Create a proportion that compares the two ratios.

\frac{8}{5}=\frac{552}{y}

Solve by cross multiplying.

8y = 5(552)

8y = 2,760

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4 0
3 years ago
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

Z_{1-\alpha /2}= Z_{0.95}= 1.645

[10.41±1.645*(\frac{3.71}{\sqrt{28} } )]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

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4 years ago
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