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Free_Kalibri [48]
3 years ago
15

You have a set of 10 cards—five red and five blue. Each group of five colored cards is numbered one through five.What is the pro

bability of drawing a red four and then a blue four, while replacing the card between the drawings?
Mathematics
2 answers:
MatroZZZ [7]3 years ago
7 0
The probability of drawing the Red 4 is 1 in 10. So, the chances of getting it would be 1/10.The probability is also the same for drawing the Blue 4, so it would be 1/10 also.

The probability assignment for this problem is the classical method which means that experimental outcomes are equally likely. So, just multiply the probability of the first event to the second event.
= 1/10 * 1/10 = 1/100
The probability of getting the blue and red four is 1/100 or 0.01.
ivann1987 [24]3 years ago
4 0
The answer is 1/100.
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Answer:

  -675

Step-by-step explanation:

The sum can be broken into parts that you know. Here, one of those parts is the sum of numbers 1 to n. That sum is given by n(n+1)/2.

\displaystyle S_{75}=\sum\limits_{n=1}^{75}{(67-2n)}=\sum\limits_{n=1}^{75}{67}-2\sum\limits_{n=1}^{75}{n}\\\\=75\cdot 67-2\dfrac{75(75+1)}{2}=75(67-76)\\\\=\bf{-675}

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Another way to do this is to realize the sequence of numbers is an arithmetic sequence with a first term of 65 and a last term of 67-2·75 = -83.

The sum of an arithmetic sequence is found by multiplying the number of terms by their average value. Their average value is the average of the first and last terms.

The average value of those 75 terms is (65 +(-83))/2 = -9, so their sum is ...

  75(-9) = -675

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Find the volumes of each separate rectangular prism, (top) 9 x 4 x 12 = 432 cubic meters, (bottom) 10x2x2 = 40 cubic meters, and then add them together to get the overall volume, 40+432 = 472 cubic meters. the strategy is using length times width times height, LxWxH. 
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