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2 years ago

If the density is 0.1 g/cm^3 and the volume is 5cm^3, what is the mass?

Chemistry

1 answer:

Novay_Z [31]2 years ago

6 0

Answer:

<h2>The answer is 0.5 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 5 cm³

density = 0.1 g/cm³

The mass is

mass = 0.1 × 5

We have the final answer as

Hope this helps you

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What is the formula, when rubidium reacts with tellurium?

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Answer:

Like other alkali metals, rubidium metal reacts violently with water. As with potassium (which is slightly less reactive) and caesium (which is slightly more reactive), this reaction is usually vigorous enough to ignite the hydrogen gas it produces.

Explanation:

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2 years ago

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If the molar absorptivity constant for the red dye solution is 5.56×104 M-1cm-1, calculate the molarity of the red dye solution

Shtirlitz [24]

Explanation:

a) Using Beer-Lambert's law :

Formula used :

$A=\epsilon \times c\times l$

where,

A = absorbance of solution = 0.945

c = concentration of solution = ?

l = length of the cell = 1.20 cm

$\epsilon$ = molar absorptivity of this solution = $5.56\times 10^4 M^{-1} cm^{-1}$

$0.945=5.56\times 10^4 M^{-1} cm^{-1}\times 1.20 \times c$

$c=1.4163\times 10^{-5} M=14.16 \mu M$

( $1\mu M=10^{-6} M$ )

14.16 μM is the molarity of the red dye solution at the optimal wavelength 519nm and absorbance value 0.945.

b) $c=1.4163\times 10^{-5} mol/L$

1 L of solution contains $1.4163\times 10^{-5}$ moles of red dye.

Mass of $1.4163\times 10^{-5}$ moles of red dye:

$1.4163\times 10^{-5}\times 879.86g/mol=0.01246 g$

$(w/v)\%=\frac{\text{Mass of solute (g)}}{\text{Volume of solvent (mL)}}\times 100$

$red(w/v)\%=\frac{0.01246 g}{1000 mL}\times 100=0.001246\%$

c) In order to dilute red dye solution by 5 times, we will need to add 1 L of water to solution of given concentration.

Concentration of red dye solution = $c=1.4163\times 10^{-5} M$

Concentration of red solution after dilution = c'

$c=c'\times 5$

$1.4163\times 10^{-5} M=c'\times 5$

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The final concentration of the diluted solution is $2.83\times 10^{-6} M$

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3 years ago

What is the mole ratio of N2 to H2 to NH3?

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Answer:

the answer is 1:3:2

Hope this helps, let me know if you need any other help, Stoichiometry is hard

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3 years ago

Which clue can be used to identify a chemical reaction as a decomposition reaction?

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Answer:

plzz mark brainliast:

Explanation:

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3 years ago

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The digit that would have to be estimated in reading this instrument would be the nearest:

wariber [46]

Answer:

The least count of vernier calipers is 0.01 g.

(B) is correct option.

Explanation:

Given that,

The digit that would have to be estimated in reading this instrument,

According to figure,

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$pitch=\dfrac{distance\ moved}{Number\ of\ complete\ rotation}$

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$Least\ count=\dfrac{pitch}{number\ of\ vernier\ scale\ division}$

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Hence, The least count of vernier calipers is 0.01 g.

(B) is correct option.

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2 years ago

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