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RideAnS [48]
3 years ago
5

Which of the following is true when 1 M KCl is diluted to semi-molar KCl?

Chemistry
1 answer:
eimsori [14]3 years ago
4 0

The solution before dilution and after dilution contains same number of moles, and water is added for dilution.

Option B

<h3><u>Explanation:</u></h3>

Suppose before dilution, the solution contains x moles of KCl in Y liter of water. Now as the concentration got halved, then the solution contains x moles of KCl in 2Y kiters of solution. So the number of moles of KCl in the solution remained constant.

Again, as the solution is diluted to half of the concentration, water must have been added with the solution to make it dilute.

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Atoms that have the same number of outer electrons
BARSIC [14]
I can see two answers, I’d go with D, but all neutral atoms, of the same element would have the same number of outer electrons. However, if you consider that some of the atoms might be ions, that would eliminate B.
4 0
3 years ago
How many molecules of N204 are in 85.0 g of N2O4?
alukav5142 [94]

Answer:

5.56 × 10^23 molecules

Explanation:

The number of molecules in a molecule can be calculated by multiplying the number of moles in that molecule by Avagadro's number (6.02 × 10^23)

Using mole = mass/molar mass

Molar mass of N2O4 = 14(2) + 16(4)

= 28 + 64

= 92g/mol

mole = 85.0/92

= 0.9239

= 0.924mol

number of molecules of N2O4 (nA) = 0.924 × 6.02 × 10^23

= 5.56 × 10^23 molecules

4 0
3 years ago
students used a balance and a graduated cylinder to collect the data shown in table 7. calculate the density of the sample. if t
Licemer1 [7]

Answer:

              Percentage error  =  1.88 %

Solution:

Data Given:

                 Mass of Sample  =  20.46 g

                 Volume of Sample  =  43.0 mL - 40.0 mL  =  3.0 mL

Formula Used:

                 Density  =  Mass / Volume

Putting values,

                 Density  =  20.46 g /  3.0 mL

                 Density  =  6.82 g.mL⁻¹

Percentage Error:

                 Experimental Value  =  6.82 g.mL⁻¹

                 Accepted Value  =  6.95 g.mL⁻¹

                 = 6.82 g.mL⁻¹ / 6.95 g.mL⁻¹ × 100  =  98.12 %

                 Percentage Error  =  100 % - 98.12 %

                Percentage error  =  1.88 %

3 0
3 years ago
If the concentration of phosphate in the cytosol is 2.0 mM and the concentration of phosphate in the surrounding fluid is 0.1 mM
Allushta [10]
<span>The correct option is C. The concentration of phosphate inside the cytosol is already greater than the concentration of phosphate in the surrounding fluid, yet, the cell still want to move more phosphate into the cell. To do this, energy is needed to move the phosphate ions against the concentration gradient, so the type of transportation requires is ACTIVE TRANSPORT.</span><span />
8 0
3 years ago
A car travels 150 meters in 3.5 seconds what is its speed?
defon

Answer:

The solution is given below.

Explanation:

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So the car traveled at a speed of 42.86 m/s.

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