1 L ------- 1000 cm³
1.45 L ----- ???
1.45 * 1000 = 1450 cm³ ( volume )
Density = 0.710 g/cm³
mass = in Kg
m = D * V
m = 0.710 * 1450
m = 1029.5 g
1 Kg ------- 1000 g
kg -------- 1029.5 g
mass = 1029.5 / 1000
mass = 1.0295 Kg
hope this helps!
Answer:
60.052 g/mol (molar mass of vinegar)
84.007g/mol (baking soda )
Answer:
The molar mass in g/mol is 121.4 g/m
Explanation:
Let's apply the Ideal Gases Law to solve this:
P . V = n . R. T
V = 125 mL → 0.125L
P = 754 Torr
760 Torr ___ 1 atm
754 Torr ____ (754 / 760) = 0.992 atm
Moles = Mass / Molar mass
0.992 atm . 0.125L = (0.495 g / MM) . 0.082 . 371K
(0.992 atm . 0.125L) / (0.082 . 371K) = (0.495 g / MM)
4.07x10⁻³ mol = 0.495 g / MM
MM = 0.495 g / 4.07x10⁻³ mol → 121.4 g/m
