If a reaction is second-order with respect to a particular reactant, when the concentration of that reactant is increased by a factor of 4, the reaction rate will increased by factor 16.
<h3>How do we calculate the rate of second order reaction?</h3>
Rate of the second order reaction will depends on the concentrations of one second-order reactant or two first-order reactants as:
Rate(1) = k[A]²
If the concentration of reactant becomes 4 times the initial concentration then rate will be:
Rate = k[4A]²
Rate(2) = 16k[A]²
Rate(2) = 16Rate(1)
Hence rate will increased by 16 times.
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The chemical agent mixed with feces to determine if blood is present is Luminol.
Answer:
the metal is gold I'd say
This is what I got hope it helps
