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RUDIKE [14]
1 year ago
13

If a reaction is second-order with respect to a particular reactant, when the concentration of that reactant is increased by a f

actor of 4, the reaction rate will _____
Chemistry
2 answers:
notka56 [123]1 year ago
7 0

Answer:

A reaction is second order with respect to a reactant.

Rate =k[A]

2

(i) If the concentration of the reactant is doubled, the rate of reaction becomes 4 times .

(ii) If the concentration of the reactant is reduced to half, the rate of reaction becomes one fourth.

Explanation:

nirvana33 [79]1 year ago
5 0

If a reaction is second-order with respect to a particular reactant, when the concentration of that reactant is increased by a factor of 4, the reaction rate will increased by factor 16.

<h3>How do we calculate the rate of second order reaction?</h3>

Rate of the second order reaction will depends on the concentrations of one second-order reactant or two first-order reactants as:
Rate(1) = k[A]²

If the concentration of reactant becomes 4 times the initial concentration then rate will be:

Rate = k[4A]²

Rate(2) = 16k[A]²

Rate(2) = 16Rate(1)

Hence rate will increased by 16 times.

To know more about second order reaction, visit the below link:
brainly.com/question/17217385

#SPJ4

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2 years ago
A chemical reaction is shown below:
BabaBlast [244]

Answer:

Mass = 8.46 g

Explanation:

Given data:

Mass of water produced = ?

Mass of glucose = 20 g

Mass of oxygen = 15 g

Solution:

Chemical equation:

C₆H₁₂O₆ + 6O₂     →   6H₂O + 6CO₂

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 20 g/ 180.16 g/mol

Number of moles = 0.11 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 15 g/ 32 g/mol

Number of moles = 0.47 mol

now we will compare the moles of water with oxygen and glucose.

               C₆H₁₂O₆           :            H₂O

                   1                   :              6

                 0.11                :           6/1×0.11 = 0.66

                   O₂               :            H₂O

                   6                   :              6

                 0.47                :           0.47

Less number of moles of water are produced by oxygen thus it will limit the yield of water and act as limiting reactant.

Mass of water produced:

Mass = number of moles × molar mass

Mass = 0.47 mol  ×18 g/mol

Mass = 8.46 g

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Explanation:

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