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Katarina [22]
3 years ago
7

PLEASE HELP! 80 points!!

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
8 0

Answer:

the metal is gold I'd say

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Stephen is baking cakes. He needs 1/4 cup of butter for each cake. One stick of butter is 1/2 a cup. How many sticks of butter d
ludmilkaskok [199]
The answer is A. 3 sticks of butter
4 0
3 years ago
1.<br> Draw the Dot Structure for Na!
stepladder [879]

Answer:

Na ·

Explanation:

Hello!

In this case, since the Lewis dot structure of any element illustrates the number of valence electrons at the outer shell; we can set up the electron configuration of sodium to obtain:

Na^1^1\rightarrow 1s^2,2s^2,2p^6,3s^1

We can see there is only one valence electron, for that reason the Lewis dot structure is:

Na ·

Whereas the dot represents the valence electron.

Best regards!

4 0
3 years ago
Amino axit X có công thức H2NCxHy(COOH)2. Cho 0,1 mol X vào 0,2 lít dung dịch H2SO4 0,5M, thu được dung dịch Y. Cho Y phản ứng v
Taya2010 [7]

Answer:

nH2SO4 = 0,1 mol

Đặt nNaOH = a; nKOH = 3a (mol)

Quy đổi phản ứng thành: {X, H2SO4} + {NaOH, KOH} → Muối + H2O

Ta có: nH+ = nOH- → 2nX + 2nH2SO4 = nNaOH + nKOH

→ 2.0,1 + 2.0,1 = a + 3a → a = 0,1

→ nH2O = nH+ = nOH- = 0,4 mol

BTKL: mX + mH2SO4 + mNaOH + mKOH = m muối + mH2O

→ mX + 0,1.98 + 0,1.40 + 0,3.56 = 36,7 + 0,4.18 → mX = 13,3 gam

→ MX = 13,3/0,1 = 133

→ %mN = (14/133).100% ≈ 10,526%

7 0
2 years ago
What are all the ways that you think knowing about the flow of energy might be useful in
Kaylis [27]

Yes the main benifit can be recyclation of energy

  • The example can be seen in powerbanks or inverters
  • The chemical energy present inside the battery can be used to convert itself into electric energy.
  • Which can help us in climate protection
4 0
3 years ago
At what substrate concentration would an enzyme with a K_cat of 30.0 s⁻¹ and a Km of 0.0050 M operate at one-quarter of its maxi
Umnica [9.8K]

Answer:

The correct answer is option B.

Explanation:

Michaelis–Menten 's equation:

v=V_{max}\times \frac{[S]}{(K_m+[S])}=k_{cat}[E_o]\times \frac{[S]}{(K_m+[S])}

V_{max}=k_{cat}[E_o]

v = rate of formation of products

[S] = Concatenation of substrate = ?

[K_m] = Michaelis constant

V_{max}= Maximum rate achieved

k_{cat} = Catalytic rate of the system

E_o = initial concentration of enzyme

We have :

v=\frac{V_{max}}{4}

[S] =?

K_m=0.0050 M

v=V_{max}\times \frac{[S]}{(K_m+[S])}

\frac{V_{max}}{4}=V_{max}\times \frac{[S]}{(0.0050 M+[S])}

[S]=\frac{0.005 M}{3}=1.7\times 10^{-3} M

So, the correct answer is option B.

8 0
3 years ago
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