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Rainbow [258]
3 years ago
13

How much energy must be absorbed by 45.0g of water to increase its temperature from 83 0°C to 303.0°C?

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
8 0

Answer: There will be 41382 J energy must be absorbed by 45.0g of water to increase its temperature from 83.0^{o}C to 303.0^{o}C.

Explanation:

Given: Mass = 45.0 g

Initial temperature = 83.0^{o}C

Final temperature = 303.0^{o}C

Formula used to calculate heat energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass of substance

C = specific heat = 4.18 J/g^{o}C (here, for water)

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 45.0 g \times 4.18 J/g^{o}C \times (303.0 - 83.0)^{o}C\\= 41382 J

Thus, we can conclude that there will be 41382 J energy must be absorbed by 45.0g of water to increase its temperature from 83.0^{o}C to 303.0^{o}C.

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