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gogolik [260]
3 years ago
8

How many whole numbers between −32 and 77?

Mathematics
2 answers:
mylen [45]3 years ago
8 0
109 numbers hope this helps :)
Brrunno [24]3 years ago
4 0
The answer is 109 bc negative numbers r still whole numbers
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Norman can type 44 words in a minute. At this rate, how many words can he type in 6 minutes?
inysia [295]

Answer:

264

Step-by-step explanation:

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2 years ago
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HELP?
poizon [28]
My "work" is to enter the equations into a graphing calculator and let it show me the answers--just as your "work" is to copy the question to Brainly.

The solutions are
  (x, y) = (-0.5, 7.5)
  (x, y) = (3, 25)

_____
When you equate the expressions for y, you get the quadratic
  2x² -5x -3 = 0
  (2x +1)(x -3) = 0
  x = -1/2 or 3
  y = 5(x +2) = 15/2 or 25

4 0
2 years ago
Am i right on this math problem?
Minchanka [31]

Answer:

Step-by-step explanation:

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2 years ago
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SOLVED
Nastasia [14]
5)
a. The equation that describes the forces which act in the x-direction: 
<span>     Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span>     Fy = 200 * sin 30 </span>

<span>c. The x and y components of the force of tension: </span>
<span>    Tx = Fx = 200 * cos 30  </span>
<span>    Ty = Fy = 200 * sin 30 </span>

d.<span>Since desk does not budge, </span><span>frictional force = Fx
                                                                        = 200 * cos 30 </span>

<span>                                                 Normal force </span><span>= 50 * g - Fy
                                                                       = 50 g - 200 * sin 30 
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction: 
    (200N)cos(30) - F_s = 0

b. The equation that describes the forces which act in the y-direction:
    F_N - (200N)sin(30) - mg = 0

c. The values of friction and normal forces will be:
     Friction force= (200N)cos(30),
     
The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N

Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N
4 0
3 years ago
Work out the answer to this problem to reduce to the simplest form 5/8-1/2=
inysia [295]
In order to subtract fractions, you need the denominators (bottom number) to be the same. \frac{1}{2} * \frac{4}{4} =  \frac{4}{8} . \frac{5}{8} - \frac{4}{8} =  \frac{1}{8}
3 0
2 years ago
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