Answer:
If there is a variable term and a constant on each side of the equation, then you will need to use the addition or subtraction property of equality once to isolate the variable term and once to isolate the constant.
( x -3 )² = y - 4
y = ( x - 3 )² + 4
One solution is located at the vertex: ( 3, 4 ).
y = - x + b
4 = - 3 + b
b = 7
( x - 3 )² = - x + 7 - 4
x² - 6 x + 9 = - x + 3
x² - 5 x + 6 = 0
x² - 2 x - 3 x + 6 = 0
x ( x - 2 ) - 3 ( x - 2 ) = 0
( x - 2 ) ( x - 3 ) = 0
x 1 = 2, x 2 = 3
y 1 = 5, y 2 = 4.
In order for this solution to be reasonable, the 2nd equation must be:
y = - x + 7
<span>Equation A: 4c = d − 8
</span><span>Equation B: c = 5d + 8
</span>
Multiply Equation A by -5:
Equation A: - 20c = -5d + 40
Equation (1) + (2) :
-19c = 48
Answer: <span>B. Multiply equation A by -5</span>
Answer:
0.5l+0.2s
Step-by-step explanation:
0.10x5<em>l</em> equals 0.5<em>l</em>
0.10x2<em>s</em> equals 0.2<em>s</em>
