$1000 is invested at 2.9% annual interest for 6 months. a. Simple Interest b. Compound Interest

Mathematics

1 answer:

kirza4 [7]3 years ago

8 0

Answer:

a. Simple interest = $174

b. Compund interest = $1187.1

Step-by-step explanation:

Given the following data;

Principal, P = $1000

Interest, R = 2.9%

Time, T = 6 months

a. To find the simple interest;

S.I = (PRT)/100

S.I = (1000*2.9*6)/100

S.I = 17400/100

S.I = $174

b. To find the compound interest;

$A = P(1 + \frac{r}{100})^{t}$

Substituting into the formula, we have;

$A = 1000(1 + \frac{2.9}{100})^{6}$

$A = 1000(1 + 0.029)^{6}$

$A = 1000(1.029)^{6}$

$A = 1000(1.1871)$

A = $1187.1

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