Answer:
-2a^4+8a^3-6a^2
Step-by-step explanation:
2a^2(a-1)(3-a)
2a^2(-a^2 +3a-3+a)
2a^2(-a^2+4a-3)
-2a^4+8a^3-6a^2
Sounds like an id 10 t problem
To find the number of even factors, we can multiply the number of odd factors by the power of 2 (not the power of 2 + 1!!!). For 540, we have (3 + 1)(1 + 1)(2) = 16 even factors.