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4 years ago

What is the lowest prime number 1,2,3,4

2 answers:

6 0

Hey there, well we know a prime number must have exactly two factors, which is 1 and its self. 2 is the lowest prime number because because the common divisors for 2 is 1 and 2. Therefore, 2 is the lowest prime number.

stira [4]4 years ago

6 0

<span>Additive primes
</span><span>
Primes such that the sum of digits is a prime.</span>

2, 3, 5, 7, 11, 23, 29, 41, 43, 47, 61, 67, 83, 89, 101, 113, 131

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SOMEONE PLEASE ANSWER ASAP!! 55 POINTS!!

nadezda [96]

Answer:

EG = 16 and FH =22

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other

so 2a = 3b+2

and 2a+3 = 6b-1

We know have a system of equations to solve

2a = 3b+2

2a+3 = 6b-1

Subtract 3 from each side

2a+3-3 = 6b-1-3

2a = 6b -4

Now we can set the 2 equations equal ( 2a = 3b+2 and 2a = 6b -4)

3b+2 = 6b-4

Subtract 3b from each side

3b-3b+2 = 6b-3b-4

2 = 3b-4

Add 4 to each side

2+4 = 3b-4+4

6 = 3b

Divide by 3

6/3 = 3b/3

2 =b

We want to find a

2a = 3b+2

Substitute in b=2

2a = 3(2) + 2

2a = 6+2

2a =8

Divide by 2

2a/2 =8/2

a = 4

Now that we know a and b

EG = 2a + 3b+2

= 2(4) + 3(2)+2

= 8+6+2

= 16

FH = 2a+3 + 6b-1

= 2(4) +3 +6(2)-1

= 8+3+12-1

= 23-1

= 22

4 0

3 years ago

Please help!!As soon as possible!!

pychu [463]

Answer: Their equations have different y-intercept but the same slope

Step-by-step explanation:

Since, the slope of the line passes through the points (2002,p) and (2011,q) is,

$m_1 = \frac{q-p}{2011-2002} = \frac{q-p}{9}$

Similarly, the slope of the line asses through the points (2,p) and (11,q) is,

$m_2 = \frac{q-p}{11-2} = \frac{q-p}{9}$

Since, $m_1 = m_2$

Hence, both line have the same slope.

Now, the equation of the line one having slope $m_1$ and passes through the point (2002,p) is,

$y - p = \frac{q-p}{9}(x-2002)$

Put x = 0 in the above equation,

We get, $y = \frac{2000(p-q)}{9}+p$

The y-intercept of the line one is $(0, \frac{2000(p-q)}{9}+p)$

Also, the equation of second line having slope $m_2$ and passes through the point (2,p)

$y-p=\frac{q-p}{9}(x-2)$

Put x = 0 in the above equation,

We get, $y = \frac{2(p-q)}{9}+p$

The y-intercept of the line one is $(0, \frac{2(p-q)}{9}+p)$

Thus, both line have the different y-intercepts.

⇒ Third option is correct.

6 0

3 years ago

One half of the sum of 3 and q

ivann1987 [24]

Here you go let me know if you have questions

7 0

4 years ago

You are considering a cylindrical container with a diameter of 14 inches and a height of 18 inches. Find the volume of this cont

Vsevolod [243]

Volume of a cylinder is (pi) times radius to the second power times height. <em></em><em />
Radius is half of the diameter, which would be 7.
Volume would be 2770.88<span />

3 0

4 years ago

Can some help me if your good at maths

Annette [7]

Answer:

36=2×3×3×3

4 0

3 years ago

Read 2 more answers