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horrorfan [7]
3 years ago
7

Ln how many ways 5 person sitted in a round table having 8 seats?

Mathematics
1 answer:
kvasek [131]3 years ago
5 0

Answer: First consider the case that ‘just’ 5 persons are seated around a round table.

Clearly, ‘just’ 5 persons can be seated around a round table in (5 - 1)! = 4! = 24 ways.

Now, one vacant chair is to be inserted among them.

Say, for a particular sitting arrangement ‘ABCDE’; there are 5 scopes available for inserting the vacant chair - between A and B, between B and C, between C and D, between D and E & between E and A.

So, there are 5*24 = 120 ways available that 5 persons can sit around a round table with 6 chairs.

Step-by-step explanation:

First consider the case that ‘just’ 5 persons are seated around a round table.

Clearly, ‘just’ 5 persons can be seated around a round table in (5 - 1)! = 4! = 24 ways.

Now, one vacant chair is to be inserted among them.

Say, for a particular sitting arrangement ‘ABCDE’; there are 5 scopes available for inserting the vacant chair - between A and B, between B and C, between C and D, between D and E & between E and A.

So, there are 5*24 = 120 ways available that 5 persons can sit around a round table with 6 chairs.

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Answer:

x=-8 ,2

Step-by-step explanation:

x ^ 2 + 6x - 6 = 10

Add 6 to each side

x ^ 2 + 6x - 6+6 = 10+6

x ^ 2 + 6x  = 16

Complete the square  take the coefficient of the x terms, divide by 2 and square it.  Then add it to each side

6/2 =3  , 3^2 =9  

x ^ 2 + 6x +9 = 16+9

(x+3)^2 = 25

Take the square root of each side

sqrt((x+3)^2) = ±sqrt(25)

x+3= ±5

Make 2 equations

x+3 = 5    x+3 = -5

Subtract 3 from each side

x+3-3 =5-3             x+3-3 = -5-3

x =2                           x=-8

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Step-by-step explanation:

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\frac{3}{4} \times\frac{7}{3}

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=\frac{21}{12} =\frac{7}{4} =1\frac{3}{4}

=1\frac{3}{4}

Hope this helps.

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