The axis of symmetry is x=-b/2a for f(x), the axis of symmetry is x=0, because there is no b. when x=0, f(x)=4*0²-1=-1, so the vertex is (0, -1) because a in this case is 4, a positive number, the parabola opens upward, -1 is the lowest value.
for g(x), x=-(-8)/2*1=4, f(x)=4²-8*4+5=-11, the vertex is (4,-11) because a is 1 in this case, a positive number, the parabola opens upward, -11 is the lowest value.
for h(x), x=-(-12)/[2*(-3)]=-2, f(x)=-3*(-2)²-12(-2)+1=13, the vertex is (-2,13) because a is -3 in this case, a negative number, 13 is the largest value.
f(x)'s is obviously larger than g(x) (the graph of f(x) is above that of g(x)), but for h(x), since it opens downward from y=13, it overwraps with part of f(x) and g(x), I'm not sure how you can compare that.
but if we look at the vertex alone, g(x) is the least, then f(x), then h(x) is the largest. I hope all this makes sense.
The answer is actually A g(x) is the lowest amount, h(x) being the middle, and f(x) being the largest, I see where you were going with it, but I think you miscalculated f(x), because it is larger than h(x)
Surface area of a square pyramid is the area of the base + 4 times the area of one of the slanted sides.
Area of base = side length * side length
Area of side = (1/2) * side length * slant height
Don't forget that you have to multiply the area of the side by 4!
Step 1: 12 x 12 = 144 Step 2: 12 x 20 = 240 divided by 2 = 120 Step 3: 144 + 120 x 4
