So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
<span>C) Right
https://www.desmos.com/calculator/vf2qksnpwe
</span>right triangle
<span>Proof: You can apply the Pythagorean theorem.</span>
Answer:
ME LOL
Step-by-step explanation:
XDHJCVEFBV,RW
Answer:
4cos4x
Step-by-step explanation:
let's use cos
amplitude=4
period=pi/2
2pi/x=pi/2
x=4
no phase shift
y=4cos4x
pic from desmos
Answer:
254 square inches
Step-by-step explanation:
A=pi*r^2
A=pi*(d/2)^2
A=3.14*(18/2)^2
A=3.14*(9)^2
A=3.14*81
A=254.34 in^2
So, rounded no the nearest whole, the answer is 254 in^2
Which is option 2 or B
