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2 years ago

What is the factorization of the trinomial below? -X^2 - 2x + 48

Mathematics

2 answers:

Gekata [30.6K]2 years ago

7 0

$\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}$

ur answer is

Thanks
hope it helps

raketka [301]2 years ago

3 0

Answer:

<h3>I think option C.</h3>

(x-6) (x-8).

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Convert 4.08 to a fraction. Help me please.

Fofino [41]

Answer:

4/8

Step-by-step explanation:0.n is = to 10. 4 is the numerator. So it would be 4/8

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2 years ago

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Sam buys 3 different types of fruit in 3/4 pounds basket. Maria has 1 1/4 pound fruit. How many pounds of fruit do they have alt

uysha [10]

Answer: 2 pounds

Step-by-step explanation: hope this helps:)

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3 years ago

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Help !!!!!!!!!!!!!!!!!!!!!!!!!!

Blizzard [7]

Step-by-step explanation:

so 5/9(86-32) then you take

86-32=(54)

now it look like C=5/9=(54)

C=30

so c=30 is the answer :)

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2 years ago

The answer is D Does not exist; does not exist

jolli1 [7]

Answer:

Have a great day too..... :)

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2 years ago

A package contains 12 resistors, 3 of which are defective. If 4 are selected, find the probability of getting

s344n2d4d5 [400]

Answer:

Incomplete question, but I gave a primer on the hypergeometric distribution, which is used to solve this question, so just the formula has to be applied to find the desired probabilities.

Step-by-step explanation:

The resistors are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

12 resistors, which means that $N = 12$

3 defective, which means that $k = 3$

4 are selected, which means that $n = 4$

To find an specific probability, that is, of x defectives:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = x) = h(x,12,4,3) = \frac{C_{3,x}*C_{9,4-x}}{C_{12,4}}$

7 0

2 years ago