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DerKrebs [107]
3 years ago
11

Ming kept track of her puppy Sampson's weight gain over a three-month time period. He was six weeks old on November 15 and weigh

ed 2.49 kilograms. On December 15, he weighed 1020 grams more. On January 15, he had gained another 2200 grams. On February 15, he had only gained 0.567 kilograms. How much weight did Sampson gain from November to February?
Mathematics
1 answer:
Kobotan [32]3 years ago
4 0

Answer:

Sampson gains 3.967 kilograms from November to February.

Step-by-step explanation:

Given:

Actual Weight on November 15 = 2.49 kg

On December 15, he weighed 1020 grams more

Since 1000 grams = 1 kg

Weight on December 15 = 1020 grams = 1.2 kg

Hence Weight gained from November 15 to December 15 = 1.2 kg

On January 15, he had gained another 2200 grams

Weight on January 15 = 2200 grams = 2.2 kg

Hence Weight gained from December 15 to January 15 = 2.2 kg

On February 15, he had only gained 0.567 kilograms.

Weight on February 15 = 0.567 kg

Hence Weight gained from January 15 to February 15 = 2.2 kg

Total weight gained from November to February = Weight gained from November 15 to December 15 + Weight gained from December 15 to January 15 + Weight gained from January 15 to February 15

Total weight gained from November to February  = 1.2+2.2+0.567 = 3.967 \ kg

Hence Sampson gained total weight of 3.967 kg from November to February.

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lara31 [8.8K]

Answer:

T = 2π√[2m/(9.8m/s²)]

5 0
3 years ago
HELP ME PLEASE
s344n2d4d5 [400]

Answer:

$1800

Step-by-step explanation:

Interest in one month =3% =0.03

0.03x5000= $150 a month

150x12=$1800

4 0
3 years ago
Need help to do this step by step please <br> 3x2 - 2x=-1
sdas [7]

Answer:

Solving the expression 3x^2-2x=-1 we get: \mathbf{x=\frac{1+\sqrt{2}i }{3}\:or\:x=\frac{1-\sqrt{2}i }{3}}

Step-by-step explanation:

We need to solve the expression: 3x^2-2x=-1

This is a quadratic expression and it can be solved using quadratic formula

Solving:

3x^2-2x=-1\\

we can write it as:

3x^2-2x+1=0

The quadratic formula is: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

where a = 3, b = -2 and c= 1

Putting values and solving:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-2)\pm\sqrt{(-2)^2-4(3)(1)}}{2(3)}\\x=\frac{2\pm\sqrt{4-12}}{2(3)}\\x=\frac{2\pm\sqrt{-8}}{6}\\We\:know\:that\:\sqrt{-1}=i\\x=\frac{2\pm\sqrt{8}\sqrt{-1} }{6} \\We\:know\:\sqrt{8}=\sqrt{2\times 2 \times 2}=\sqrt{2^2 \times 2}=2\sqrt{2}   \\x=\frac{2\pm2\sqrt{2}i }{6}\\Now,\\x=\frac{2+2\sqrt{2}i }{6}\:or\:x=\frac{2-2\sqrt{2}i }{6}\\x=\frac{2(1+\sqrt{2}i) }{6}\:or\:x=\frac{2(1-\sqrt{2}i) }{6}\\x=\frac{1+\sqrt{2}i }{3}\:or\:x=\frac{1-\sqrt{2}i }{3}

So, solving the expression 3x^2-2x=-1 we get: \mathbf{x=\frac{1+\sqrt{2}i }{3}\:or\:x=\frac{1-\sqrt{2}i }{3}}

8 0
3 years ago
PLEASE HELP! BRAINLIEST!!!!!!! PLEASE
Gnesinka [82]
Hello!

First you have to find the volume of the cylinder

To find the volume of a cylinder you use the equation

V =  \pi  r^{2} h

V is volume
r is radius
h is height

Put in the values you know and 3.14 for pi

V = 3.14 *  3^{2} * 7

Square the number

V = 3.14 * 9 * 7 

Multiply

V = 197.82
------------------------------------------------------------------------------------------------------
Next you find the volume of the sphere

To find the volume of a sphere you use the equation

V =  \frac{4}{3}  \pi  r^{3}

V is volume
r is radius

Put in the values you know and 3.14 for pi

V =  \frac{4}{3} * 3.14 *  3^{3}

Cube the number

V =  \frac{4}{3} * 3.14 * 27

Multiply

V = 113.04
------------------------------------------------------------------------------------------------------
Finally you subtract the two volumes from each other

197.82 - 113.04 = 84.78
------------------------------------------------------------------------------------------------------
The answer is C)84.78

Hope this helps!
7 0
3 years ago
Read 2 more answers
Pleaseeeeeeee help me
Juli2301 [7.4K]

Answer:

The answer is "The discriminant is positive"

Step-by-step explanation:

When the discriminant is positive there is two real solutions.

When the discriminant is equal to 0, there is one real solution.

When the discriminant is negative, there is no real number solutions.

8 0
3 years ago
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