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kicyunya [14]
2 years ago
11

Solve x^(2)+4x=4 for x by completing the square.

Mathematics
1 answer:
Mama L [17]2 years ago
8 0

Answer:

x = 2 sqrt(2) - 2 or x = -2 - 2 sqrt(2)

Step-by-step explanation:

Solve for x:

x^2 + 4 x = 4

Add 4 to both sides:

x^2 + 4 x + 4 = 8

Write the left hand side as a square:

(x + 2)^2 = 8

Take the square root of both sides:

x + 2 = 2 sqrt(2) or x + 2 = -2 sqrt(2)

Subtract 2 from both sides:

x = 2 sqrt(2) - 2 or x + 2 = -2 sqrt(2)

Subtract 2 from both sides:

Answer: x = 2 sqrt(2) - 2 or x = -2 - 2 sqrt(2)

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At Katya’s fruit stand, a basket of strawberries costs $4 and a basket of raspberries costs $9. In one morning, Katya sells 96 b
Tcecarenko [31]

Answer:

The number of strawberry baskets sold was 44

Step-by-step explanation:

Let

x ----> the number of strawberry baskets sold

y ---> the number of raspberries baskets sold

we know that

In one morning, Katya sells 96 baskets for $644

so

x+y=96 ----> equation A

4x+9y=644 ---> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (44.52)

see the attached figure

therefore

The number of strawberry baskets sold was 44 and the number of raspberries baskets sold was 52

4 0
3 years ago
Which expression is equivalent to x³ - x² - 14x + 24?
serg [7]

Answer:

<h3>A. ( x - 2 )( x - 3 )(x + 4 )</h3>

<h3>Step-by-step explanation:</h3>

<h3>x³ - x² - 14x + 24</h3>

<h3>1. Use the rational root theorem</h3>

= (x  - 2) \frac{x ^{3}  -x^{2}  - 14x + 24}{x - 2}

<h3>2. \frac{  {x}^{3} - {x}^{2}  - 14x + 24 }{x - 2}  =  {x}^{2}  + x - 12</h3><h3 />

= ( x - 2 )( x² + x - 12 )

<h3>3. Factor x² + x - 12 : ( x -3 )( x + 4)</h3>

= ( x - 2 )( x - 3 )(x + 4 )

<h3>Solution : </h3>

<h3>= ( x - 2 )( x - 3 )(x + 4 )</h3>
3 0
1 year ago
Find the sum of 2x2 3x - 4, 8 - 3x, and -5x2 2. -3x2 - 2 -7x2 - 2 -3x2 6 -7x2 - 6x - 2
Law Incorporation [45]
-3x to the second power - 2

I believe this is your answer. 
4 0
3 years ago
Hello help me with this question thanks in advance​
Ede4ka [16]

\bold{\huge{\green{\underline{ Solutions }}}}

<h3><u>Answer </u><u>1</u><u>1</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

\sf{HM = 5 cm }

  • <u>In </u><u>square </u><u>all </u><u>sides </u><u>of </u><u>squares </u><u>are </u><u>equal </u>

<u>The </u><u>perimeter </u><u>of </u><u>square </u>

\sf{ = 4 × side }

\sf{ = 4 × 5 }

\sf{ = 20 cm }

Thus, The perimeter of square is 20 cm

Hence, Option C is correct .

<h3><u>Answer </u><u>1</u><u>2</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

\sf{MX  = 3.5 cm }

  • <u>In </u><u>square</u><u>,</u><u> </u><u>diagonals </u><u>are </u><u>equal </u><u>and </u><u>bisect </u><u>each </u><u>other </u><u>at </u><u>9</u><u>0</u><u>°</u>

<u>Here</u><u>, </u>

\sf{MX  = MT/2}

\sf{MT = 2 * 3.5 }

\sf{MT = 7 cm}

Thus, The MT is 7cm long

Hence, Option C is correct .

<h3><u>Answer </u><u>1</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>measure </u><u>of </u><u>Ang</u><u>l</u><u>e</u><u> </u><u>MAT</u>

  • <u>All </u><u>angles </u><u>of </u><u>square </u><u>are </u><u>9</u><u>0</u><u>°</u><u> </u><u>each </u>

<u>From </u><u>above </u>

\sf{\angle{MAT  = 90° }}

Thus, Angle MAT is 90°

Hence, Option B is correct .

<h3><u>Answer </u><u>1</u><u>4</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>know </u><u>that</u><u>, </u>

  • <u>All </u><u>the </u><u>angles </u><u>of </u><u>square </u><u>are </u><u>equal </u><u>and </u><u>9</u><u>0</u><u>°</u><u> </u><u>each </u>

<u>Therefore</u><u>, </u>

\sf{\angle{MHA  = }}{\sf{\angle{ MHT/2}}}

\sf{\angle{MHA = 90°/2}}

\sf{\angle {MHA = 45°}}

Thus, Angle MHA is 45°

Hence, Option A is correct

<h3><u>Answer </u><u>1</u><u>5</u><u> </u><u>:</u><u>-</u><u> </u></h3>

Refer the above attachment for solution

Hence, Option A is correct

<h3><u>Answer </u><u>1</u><u>6</u><u> </u><u>:</u><u>-</u><u> </u></h3>

Both a and b

  • <u>The </u><u>median </u><u>of </u><u>isosceles </u><u>trapezoid </u><u>is </u><u>parallel </u><u>to </u><u>the </u><u>base</u>
  • <u>The </u><u>diagonals </u><u>are </u><u>congruent </u>

Hence, Option C is correct

<h3><u>Answer </u><u>1</u><u>7</u><u> </u><u>:</u><u>-</u></h3>

In rhombus PALM,

  • <u>All </u><u>sides </u><u>and </u><u>opposite </u><u>angles </u><u>are </u><u>equal </u>

Let O be the midpoint of Rhombus PALM

<u>In </u><u>Δ</u><u>OLM</u><u>, </u><u>By </u><u>using </u><u>Angle </u><u>sum </u><u>property </u><u>:</u><u>-</u>

\sf{35° + 90° + }{\sf{\angle{ OLM = 180°}}}

\sf{\angle{OLM = 180° - 125°}}

\sf{\angle{ OLM = 55° }}

<u>Now</u><u>, </u>

\sf{\angle{OLM = }}{\sf{\angle{OLA}}}

  • <u>OL </u><u>is </u><u>the </u><u>bisector </u><u>of </u><u>diagonal </u><u>AM</u>

<u>Therefore</u><u>, </u>

\sf{\angle{ PLA = 55° }}

Thus, Angle PLA is 55° .

Hence, Option C is correct

8 0
2 years ago
The points H, I, J and K all lie on the same line segment, in that order, such that the
tresset_1 [31]

Answer:

IJ = 12

Step-by-step explanation:

sum the parts of the ratios, 3 + 3 + 4 = 10 parts

Divide HK by 10 to find the value of one part of the ratio.

40 ÷ 10 = 4 ← value of 1 part of ratio , then

IJ = 3 parts = 3 × 4 = 12

6 0
3 years ago
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