Explanation:
It is given that,
Wavelength of x-rays = 2 nm
Plane spacing, d = 0.281 nm
It is assumed to find the scattering angle for second order maxima.
For 2nd order, Bragg's law is given by :
For second order, n = 2
Here, θ is not defined. Also, the wavelength of x-rays is more than the plane spacing. It means that it cannot produce any diffraction maximum.
The maximum value of Force is 7.88x
The minimum value of magnetic force is 0
Potential V=2.40x.
Magnetic field = B = 1.70 T.
we need to find
a) The maximum value of Force
Since the particle is moving from rest, the potential energy change is 2.40x?
Potential Energy= vq= 2,40xx (-1.6 x 10x
%).
= -8.84x
Now this will be equal to 1/2 mv²
= 1/2 mv²= 8.84x .
v=2.903xm/s :
Wow Fmax = qvb
=1.6xx2.903x
x1.70 .
=7.88x
b) The minimum value of magnetic force
The minimum Value of magnetic force will be
when sinθ=0
The minimum value is 0
To know more about magnetic field refer to brainly.com/question/13091447
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Answer:
a
b
Explanation:
From the question we are told that
The distance of separation is
The is distance of the screen from the slit is
The distance between the central bright fringe and either of the adjacent bright
Generally the condition for constructive interference is
From the question we are told that small-angle approximation is valid here.
So
=>
=>
Here n is the order of maxima and the value is n = 1 because we are considering the central bright fringe and either of the adjacent bright fringes
Generally the distance between the central bright fringe and either of the adjacent bright is mathematically represented as
From the question we are told that small-angle approximation is valid here.
So
=>
So
substituting values
In the b part of the question we are considering the next set of bright fringe so n= 2
Hence