Answer:
C)Both A and B
Explanation:
It is best practice to replace the worn out tie rod with Pairs instead of a single tie rod. It is not absolutely necessary, but many technicians insist on replacing both even if only one is worn out. This is because both have more or less the same load and sooner or later the other one is going to fail too. That's why technician A said that outer tie rod ends should be replaced in pairs, even if only one is worn. Technician B said that inner tie rod ends should be replaced in pairs, even if only one is worn. Both the technicians are correct
Fat-soluble DDT accumulates in the fats of milk and from there can be transferred to children.
Answer:
a) 0.9995c
b) 5641MeV
c) 91670 MeV
Explanation:
(a) The speed of approach is given by the formula:

(b) the kinetic energy is given by:
![E_k=m_0c^2[\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}-1]](https://tex.z-dn.net/?f=E_k%3Dm_0c%5E2%5B%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%5Cfrac%7Bv%5E2%7D%7Bc%5E2%7D%7D%7D-1%5D)
by replacing c=3*10^8m/s, m_0=1.67*10^{-27}kg we obtain:

(c) in the rest frame of the other proton we have:
![E_k=m_0c^2[\frac{1}{\sqrt{1-\frac{u^2}{c^2}}}-1]](https://tex.z-dn.net/?f=E_k%3Dm_0c%5E2%5B%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%5Cfrac%7Bu%5E2%7D%7Bc%5E2%7D%7D%7D-1%5D)
by replacing we get

hope this helps!!
Answer:
It is just a theory that multi verse exists. Researchers have found tracers of mirror particles which could only be from other universe.
Explanation:
Its said above.
Answer:
the required revolution per hour is 28.6849
Explanation:
Given the data in the question;
we know that the expression for the linear acceleration in terms of angular velocity is;
= rω²
ω² =
/ r
ω = √(
/ r )
where r is the radius of the cylinder
ω is the angular velocity
given that; the centripetal acceleration equal to the acceleration of gravity a
= g = 9.8 m/s²
so, given that, diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m
Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m
so we substitute
ω = √( 9.8 m/s² / 3909.87 m )
ω = √0.002506477 s²
ω = 0.0500647 ≈ 0.05 rad/s
we know that; 1 rad/s = 9.5493 revolution per minute
ω = 0.05 × 9.5493 RPM
ω = 0.478082 RPM
1 rpm = 60 rph
so
ω = 0.478082 × 60
ω = 28.6849 revolutions per hour
Therefore, the required revolution per hour is 28.6849