Answer:
Well, their are two answers in their. It would be Ask their Parent for assistance in persuading and Ask for an opportunity to earn extra credit:)
Explanation:
The answer to this question would be a transverse wave, because the vibration travels parallel to the direction that the wave is traveling.
A force is a push or pull upon an object resulting from the object's interaction with another object.
-- Bob covered a distance of (32m + 45m) = 77 meters.
-- His displacement is the straight-line distance and direction
from his starting point to his ending point.
The straight-line distance is
D = √(32² + 45²)
D = √(1,024 + 2,025)
D = √3,049 = 55.22 meters
The direction is the angle whose tangent is (32/45) south of east.
tan⁻¹(32/45) = tan⁻¹(0.7111...) = 35.42° south of east.
Answer:

Explanation:
Here by ideal gas equation we can say

now we know that pressure is kept constant here
so we will have

since we know that number of moles and pressure is constant here
so we have

now we know that initial temperature is 17.8 degree C
and finally volume is doubled
So we have

so final temperature will be

