Answer:
is a solution
Step-by-step explanation:
Given


Required
Determine if
is a solution
becomes

--- this is true


--- this is also true
Hence,
is a solution
Answer:
1:3
Step-by-step explanation:
That ratio would be 5 :15 or 1:3
Answer:
a) t₀ = 1.73205 s
b) 1.0 C
Step-by-step explanation:
(A)
The time dilation (t) observed by an observer at rest relative to the time (t₀) measured by observer in motion is;

time measured by captain
⇒
V = 0.5 c
⇒ t₀ = 1.73205 s
(B)
Speed of the light never exceeds by its real value. The speed of the light in any frame of reference is constant.
∵ It will be "1.0C" or just "C"
<span>In
4 weeks, it dropped 3 feet in total.
The unit rate of this is 3 feet / 4 weeks
If we simplify this into days, this will be the solutions
=> 4 weeks has (4 * 7) 28 days in total, so we need to divide 3 feet by 28
days to get the simplified unit rate.
=> 3 feet / 28 days
=> .107 feet / day.
So the water drops .107 feet per day and in 4 weeks the total of 3 feet.</span>
Answer:
0.02116402116
Or otherwise written as- 0.211