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makkiz [27]
3 years ago
8

I WILL GIVE BRAILIEST IF ANSWER IS CORRECT! The sum of all the solutions to the equation (6x+k)(3x-11)=0 is 1. Find K. Please he

lp me I don't understand what this problem means.
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
7 0

Answer:

k=-6x

Step-by-step explanation:

You are looking for the value of k.

Either (6x+k)=0, or (3x-11)=0 because of the Zero Product Property

We are looking for k, so we must make (6x+k)=0

Simply cancel 6x out by subtracting 6x.

6x-6x=0.

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a ticket office sold 553 tickets one day. the receipts totaled $3936. how many $9 adult tickets and how many $6 child tickets we
Vsevolod [243]

This is the assumption method ;)

Take all tickets to be adult tickets

$9 x 553 = $4977

Then..... $4977 - $3936 = $1041

The difference between the child and adult ticket is $3, so divide $1041 by $3

$1041 divided by $3 = 347

347 is the number of <em>child </em>tickets sold

347 x $6 = $2082

So 553 - 347 = 206 ( no. of adult tickets )

206 x $9 = $1854

Child tickets sold : 347

Adult tickets sold : 206

:0 ITS MAGIC IM SO SMART

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Step-by-step explanation:

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SpyIntel [72]
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3 0
3 years ago
X squared minus 7x plus 10 equals 0
joja [24]
X² - 7x + 10 = 0

Let's factor out the equation first.

x² - 7x + 10

x             -2
x             -5

This factoring of (x-2)(x-5) fit the equation.

(x-2)(x-5) = 0

One of the factors must equal 0 as to equal zero.

Either x - 2 = 0 or x - 5 = 0

x - 2 = 0 
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