Question

find the equation of the straight line passing through the point (0,-1) which is perpendicular to the line y=-3/4x-3

Answer 1

Answer:

y = $\frac{4}{3}$ x - 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - $\frac{3}{4}$ x - 3 is in this form

with slope m = - $\frac{3}{4}$

the slope of a perpendicular line is the negative reciprocal of m, hence

$m_{perpendicular}$ = $\frac{4}{3}$

(0 , - 1 ) is the y-intercept ⇒ c = - 1

y = $\frac{4}{3}$ x - 1  ← equation of perpendicular line