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polet [3.4K]
3 years ago
15

find the equation of the straight line passing through the point (0,-1) which is perpendicular to the line y=-3/4x-3

Mathematics
1 answer:
barxatty [35]3 years ago
4 0

Answer:

y = \frac{4}{3} x - 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - \frac{3}{4} x - 3 is in this form

with slope m = - \frac{3}{4}

the slope of a perpendicular line is the negative reciprocal of m, hence

m_{perpendicular} = \frac{4}{3}

(0 , - 1 ) is the y-intercept ⇒ c = - 1

y = \frac{4}{3} x - 1  ← equation of perpendicular line


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