Answer:
A.) 27000 kgm/s
18000 kgm/s
B.) Va = 22 m/s
C.) 19800 kgm/s
25200 kgm/s
Explanation: Given that the velocity of A and B are 30 m/s and 20 m/s. And of the same mass M = 9 × 10^5g
M = 9×10^5/1000 = 900 kg
A.) Initial momentum of A
Mu = 900 × 30 = 27000 kgm/s
Initial momentum of B
Mu = 900 × 20 = 18000 kgm/s
B.) if they have an accident and then the velocity of the B is 28 m/s, find out velocity of A.
Momentum before impact = momentum after impact
Given that Vb = 28 m/s
27000 + 18000 = 900Va + 900 × 28
45000 = 900Va + 25200
900Va = 45000 - 25200
900Va = 19800
Va = 19800/900
Va = 22 m/s
C.) Momentum of A after impact
MV = 900 × 22 = 19800 kgm/s
Momentum of B after impact
MV = 900 × 28 = 25200 kgm/s
Answer: No
Explanation:they do not exist electric field lines are only imaginary
Answer:
(a) 2.3 x 10^-12 N
(b) 1.6 x 10^5 m/s
Explanation:
q1 = 1.6 x 10^-19 C
q2 = 1.6 x 10^-19 C
r = 1 x 10^-8 m
(a) the electrostatic force is given by
F = K q1 x q2 / r^2
F = ( 9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (1 x 10-^-8)^2
F = 2.3 x 10^-12 N
The force is attractive in nature because the nature of charge on electron and proton s opposite to each other.
(b) The electrostatic force is balanced by the centripetal force actig on the electron.
F = mv^2 / r
where, r be the radius of orbit and v be the velocity of electron in the orbit.
2.3 x 10^-12 = (9.1 x 10^-31 x v^2) / (1 x 10^-8)
v = 1.6 x 10^5 m/s
C IS THE CORRECT answer TO THE QUESTION
