Answer:
3.416 m/s
Explanation:
Given that:
mass of cannonball 
= 72.0 kg
mass of performer 
= 65.0 kg
The horizontal component of the ball initially 
= 6.50 m/s
the final velocity of the combined system v = ????
By applying the linear momentum of conservation:
v = 3.416 m/s
Answer:
The charge on the drop is
q = 1.741 x 10 ⁻²¹ C
Explanation:
Electric field due to plates
Ef = V/d
Ef = 2033 V / (2.0 * 10^-2 m )
Ef = 101650 V/m
So, we can write
Ef * q = m*g
q = m*g / E
f
The mass can be equal using the density and the volume so:
m = ρ * v
The volume can be find as:
v = 2.298 x 10 ⁻ ¹⁶ m³
q = ρ * v * g / Ef
q = 81 x 10 ³ kg/ m³ * 2.2298 x 10 ⁻ ¹⁶ m³ * 9.8 m/s² / 101650 V/m
The charge on the drop is
q = 1.741 x 10 ⁻²¹ C
Answer:
The male gamete is smaller in comparison to that of the female gamete.
The male gamete is conical from the front while the female gamete is spherical.
The cytoplasm in the male gamete is less in comparison to that of the female gamete.
The male gamete can move with the help of the tail while the female gametes are immobile and do not have any tail or flagella present.
The number of mitochondria present in the sperm is less than the number of mitochondria present in the ovum.
The male gamete has acrosome present in the head region that contains enzymes for dissolving the membranes present around the ovum. The ovum does not contain such digestive enzymes.
Explanation:
Answer:
F = 7.2N
Explanation:
The resultant of two forces acting at some angle is given by using the vector addition as given below
F =√F1^2+F2^2+2F1F2cosθ
Where F1 = 6N and F2 = 8N
θ = 240°
Substituting the values into the equation above
F = √ 6^2+8^2+ 2(6×8)cos240
F =√ 36+64+96cos240
F = √ 100+96 ×-0.5
F = √ 100-48
F = √ 52
F = 7.211
F = 7.2N
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