A 20×10⁹charge is moved between two points A andB that are 30mm apart and have an electric potential difference of 600v between
them. calculate a) the electric field strength between A and B b)the work done on the charge.
1 answer:
Answer:
90x20=1800
Explanation:
just multiply 10 & 9 and then mutiply 90x20 or 20x90
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