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Lapatulllka [165]
4 years ago
14

A scientist wants to model an internal organ with connective tissue as a mass on a spring. The mass of the organ is 2.0 kg, and

its natural period of oscillation is 0.12s. What would be the spring constant for the spring in the scientist's model?
Physics
1 answer:
vichka [17]4 years ago
5 0

Answer:

Spring constant, k = 5483.11 N/m

Explanation:

It is given that,

Mass of the organ, m = 2 kg

The natural period of oscillation is, T = 0.12 s

Let k is the spring constant for the spring in the scientist's model. The period of oscillation is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

k=\dfrac{4\pi^2 m}{T^2}

k=\dfrac{4\pi^2 \times 2\ kg}{(0.12\ s)^2}

k = 5483.11 N/m

So, the  spring constant for the spring in the scientist's model is 5483.11 N/m.

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4. A meter has a resistance of 100 Ω and gives a full scale deflection when it carries a current of 25 μA. (a) What resistor, Rx
frez [133]

Answer:

A=50mΩ

B≅50mΩ

Explanation:

A) To answer this question we have to use the Current Divider Rule. that rule says:

Ix=.\frac{Req}{Rx} *Itotal (1)

Itotal represents the new maximun current, 50mA, Ix is the current going through the 100 ohms resistor, and Req. is the equivalent resitor.

We now have a set of two resistor in parallel, so:

Req.=\frac{1}{\frac{1}{R1}+\frac{1}{R2}  } (2)

where R1 is the resitor we have to calculate, and R2 is the 100 ohms resistor (25 uA).

substituting and rearranging (2)

Req.=\frac{ 100*R1}{R1+100} (3)

Now substituting (3) in (1).

25*10^{-6} =\frac{\frac{ 100*R1}{R1+100}}{100} *50*10^{-3}

solving this, The value of R1 is: 50mΩ

This value of R1 will guaranty that the ammeter full reflection willl be at 50mA.

Given that R2 (100ohm) it too much bigger than 50mΩ, the equivalent resistor will tend to 50mΩ

If you substitude this values on (2) Req. will be 49.97 mΩ.

7 0
3 years ago
Which quantity or quantities is/are increasing for the object represented by line B?
torisob [31]

Answer:

C. Velocity and Position

Explanation:

7 0
3 years ago
10 POINTS! FIRST TO ANSWER ****CORRECTLY**** GETS BRAINLIEST!
ZanzabumX [31]

Answer:

The state of California experiences periodic occurrences of higher than average precipitation. This causes flooding due to heavy rainfall.

Explanation:

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5 0
3 years ago
Read 2 more answers
A wire of length L is wound into a square coil with 167 turns and used in a generator that operates at 60.0 Hz and 120 V rms val
Mrac [35]

Answer:

171.43m

Explanation:

First, define emf( electromotive force )-is the unit electric charge imparted by an energy source. In this case the generator.

The peak emf is:

E_p_e_a_k=\sqrt2(E_m_a_x)=\sqrt(2\times 120V)=170V

Substituting w=2\pi f and the value for peaf E gives:

Total length=4\sqrt {\frac{NE_p_e_a_k}{Bw}=4\sqrt{\frac{167\times 170}{0.041T\times 2pi \times 60.0Hz}

=171.43m

Hence, wire's length is 171.43m

8 0
3 years ago
1. A truck was pulling a R.V. Away from the end of the cliff. The chain broke and the RV fell to the ground. If the truck had an
shepuryov [24]

Answer:

The force of impact, F = 17682.18 N

Explanation:

Given,

The initial velocity of the truck and associated velocity of RV, u = 2 m/s

The height of the cliff, h = 280 ft

                                        = 85.344 m

The mass of the RV, m = 1800 Kg

The total energy of the RV at height, 'h' with velocity, 'v', E = P.E + K.E

                                P.E = mgh J

                                       = 1800 x 9.8 x 85.344

                                      = 1505468.16 J

                                K.E = mv²/2

                                       = 1800 x 2² / 2

                                      =3600 J

Therefore total energy, E = 1509068.16 J

This is equal to the kinetic energy of RV at the impact.

The force of impact,

                                      F = E/h

                                         = 1509068.16 J / 85.344 m

                                         = 17682.18 N

Hence, the force of impact of RV is, F = 17682.18 N

8 0
3 years ago
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