Answer:
10.44
Step-by-step explanation:
First plot each of the points on to a graph at their respective positions.
Following that create a 90° triangle out of the points. This will create a 3 by 10 triangle. (3 to 0 is 3) (-8 to 2 is a difference of 10)
You can then use the pythagorean theorem 
.
Insert the lengths of each of the sides that we got earlier which would be 3 and 10 into the equation. 
Since we want to find the hypotenuse which is equal to c we work the equation to 9+100 = 
which in turn is 109 =
Then take the square root of 109 to remove the square from the c to get c = 10.44
Answers:
A''(3, 0); B''(3, 2); C''(1, 1); D''(1, -1)
Explanation:
We perform the reflection across y=x first. This reflection switches the x- and y-coordinates; this maps:
A(2, 4)→A'(4, 2)
B(4, 4)→B'(4, 4)
C(3, 2)→C'(2, 3)
D(1, 2)→D'(2, 1)
Next we perform the translation. This translation shifts the figure 1 unit left and 2 units down, by subtracting 1 from the x-coordinate and 2 from the y-coordinate. This maps:
A'(4, 2)→A''(3, 0)
B'(4, 4)→B''(3, 2)
C'(2, 3)→C''(1, 1)
D'(2, 1)→D''(1, -1)
To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
The firts thig we are going to do is create tow triangles using the angles of elevation of Paul and Jose. Since the problem is not giving us their height we'll assume that the horizontal line of sight of both of them coincide with the base of the tree.
We know that Paul is 19m from the base of the tree and its elevation angle to the top of the tree is 59°. We also know that the elevation angle of Jose and the top of the tree is 43°, but we don't know the distance between Paul of Jose, so lets label that distance as
.
Now we can build a right triangle between Paul and the tree and another one between Jose and the tree as shown in the figure. Lets use cosine to find h in Paul's trianlge:
Now we can use the law of sines to find the distance
between Paul and Jose:
Now that we know the distance between Paul and Jose, the only thing left is add that distance to the distance from Paul and the base of the tree:
We can conclude that Jose is 33.9m from the base of the tree.
The equivalent ratio is 8 : 4.
And the missing values are as follows 21, 6 and 48.
Complete table be,
Plum 14 42 6 48
Grape 7 21 3 24
Given, a ratio table
Plum 14 42 __ __
Grape 7 __ 3 24
we have to find the missing values and the equivalent ratios.
in the first ratio,
Plum : Grape = 14 : 7 = 2 : 1
Now, in the second ratio,
2 : 1 = 42 : __
x = 21
Now, in the third ratio,
2 : 1 = __ : 3
x = 6
Now, in the forth ratio,
2 : 1 = __ : 24
x = 48
So, the equivalent ratio is 8 : 4.
And the missing values are as follows 21, 6 and 48.
Hence, the equivalent ratio is 8 : 4.
And the missing values are as follows 21, 6 and 48.
Complete table be,
Plum 14 42 6 48
Grape 7 21 3 24
Learn more about Ratios and Proportions here brainly.com/question/26974513
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