All categories

4 years ago

Ⓗⓘ քɛօքlɛ

Mathematics

2 answers:

Elza [17]4 years ago

7 0

The answer to this, maybe.., is 180

oee [108]4 years ago

7 0

They add up to 180 i have to write this to be 20 words so ignore this part btw how is your day going?

You might be interested in

2007 divided by j = 223

Effectus [21]

J = 9 because 2007 / 223 = 9, and when you multiply 223 x 9, you get 2007

8 0

4 years ago

A pen cost half as much as a ruler. Write an expression to describe how much the pen cost, using r as the cost of the ruler.

gregori [183]

Answer:

r=2p

Step-by-step explanation:

If r is ruler and p is pen, ruler equals pen times 2, so its r=2p

6 0

3 years ago

PLS HELP WILL GIVE BRAINLIEST !! TELL IF IM RIGHT AND WHY

Verdich [7]

Answer:

3rd

Step-by-step explanation:

8 0

3 years ago

An equation of the line that passes through point (0, 3) and whose slope is - 2/5?

elena-14-01-66 [18.8K]

Answer:

y=-2/5x + 3 is the eq of the line

3 0

3 years ago

. The time required for a technician to machine a specific component is normally distributed with a mean of 2 hours and a standa

erma4kov [3.2K]

Answer:

a) There is a 3.84% probability that the technician can machine one component in 1.5 hours or less.

b) There is a 0.42% probability that the technician will require at least 2.75 hours to complete one component

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.

In this problem, we have to be careful. The mean is in hours, while the standard deviation is in minutes. I am going to work with both in hours, as the problem states. 17 minutes is 0.283 hours, so:

$\mu = 2, \sigma = 0.283$

(a.) What is the probability that the technician can machine one component in 1.5 hours or less?

This probability is the pvalue of the Zscore when $X = 1.5$ . So:

$Z = \frac{1.5 - 2}{0.283}$

$Z = \frac{-0.5}{0.283}$

$Z = -1.77$

$Z = -1.77$ has a pvalue of 0.0384.

This means that there is a 3.84% probability that the technician can machine one component in 1.5 hours or less.

(b.) What is the probability that the technician will require at least 2.75 hours to complete one component?

The pvalue of the score of $X = 2.75$ is the probability that the technican will require less than 2.75 hours to complete one component. The probability that he will require at least 2.75 hours to complete one component is 1 subtracted by this pvalue. So:

$Z = \frac{2.75 - 2}{0.283}$

$Z = \frac{0.75}{0.283}$

$Z = 2.65$

$Z = 2.65$ has a pvalue of 0.99598.

This means that the probability that the technican will require at least 2.75 hours to complete one component is 1 - 0.99598 = 0.0042 = 0.42%.

4 0

4 years ago